Class 12 Chemistry · NCERT Chapter 10 (Part 3)
~13 min readBiomolecules Class 12 Chemistry Notes
Biomolecules are the molecules of life: carbohydrates, proteins, nucleic acids, vitamins, enzymes and hormones. This chapter covers the structure of glucose, reducing and non-reducing sugars, amino acids and peptide bonds, DNA double helix, enzymes and vitamins.
Why is sucrose a non-reducing sugar while glucose is reducing?
Reducing sugars have a free anomeric –OH (hemiacetal/hemiketal) that opens to an aldehyde and reduces Fehling's/Tollen's. In sucrose the aldehyde of glucose and the ketone of fructose are BOTH locked in the glycosidic bond between their anomeric carbons, so neither can open — sucrose gives no silver mirror and no red Cu₂O.
Carbohydrates: Classification
Carbohydrates
Polyhydroxy aldehydes or ketones (or compounds that hydrolyse to them). They store and provide energy — glucose in blood, starch in plants, glycogen in animals — and build structure (cellulose).
- Monosaccharides: simplest, e.g. glucose (C₆H₁₂O₆), fructose.
- Disaccharides: two sugars joined, e.g. sucrose = glucose + fructose; maltose = glucose + glucose.
- Polysaccharides: many units, e.g. starch, cellulose, glycogen.
- Optical activity: all monosaccharides rotate plane-polarised light (D/L, α/β).
Know these formulas
MCQ Questions
Structure of Glucose and Sugars
Glucose exists as an open-chain aldohexose and, in water, largely as a six-membered cyclic hemiacetal (pyranose). The new chiral centre made when the ring closes is the anomeric carbon — the −OH there pointing down gives α-D-glucose, up gives β-D-glucose, and the two interconvert (mutarotation).
- Open chain: aldehyde + 4 stereocentres + CH₂OH ⇒ D-glucose.
- Ring: cyclic hemiacetal; Haworth projection shows pyran ring with the anomeric −OH.
- Mutarotation: α (+112°) ⇌ open ⇌ β (+18.7°), equilibrium +52.7°.
- Fructose is a ketohexose; the ring is furanose for fructose, pyranose for glucose.
Reducing sugar definition
MCQ Questions
Proteins and Amino Acids
Amino acid
A compound with both −NH₂ and −COOH on the same α-carbon: H₂N–CHR–COOH. Zwitterionic (H₃N⁺–CHR–COO⁻) in solution; amphoteric — acts as acid or base.
- Essential (cannot be made in the body: valine, leucine, isoleucine...) vs non-essential amino acids.
- Peptide bond: −NH–CO− formed by condensation of the acid of one and amine of the next amino acid.
- Primary structure = amino acid sequence; secondary = α-helix/β-sheet (H-bonding); tertiary = folding in 3D; quaternary = multiple chains.
- Denaturation: heat, acid or urea unfolds the structure (boiled egg — irreversible).
- Tests: biuret (violet, peptide bonds), ninhydrin (blue-purple, free amino groups).
10 essential
MCQ Questions
Nucleic Acids: DNA and RNA
- Nucleotide = nitrogenous base + sugar (ribose or deoxyribose) + phosphate; nucleoside = base + sugar only.
- DNA: double helix (Watson–Crick), 2‑deoxyribose, bases A, T, G, C paired A‑T and G‑C via H-bonds.
- RNA: single strand, ribose, U replaces T; messenger (mRNA), transfer (tRNA), ribosomal (rRNA) RNA.
- Replication: each strand templates a complement — genetic information storage and transfer.
Nucleoside vs nucleotide
MCQ Questions
Vitamins and Enzymes
- Vitamins: essential organic micronutrients. Fat-soluble: A, D, E, K (stored in fat). Water-soluble: B‑complex, C (excreted daily, must be replenished).
- Deficiency table: A → night blindness; B1 (thiamine) → beriberi; C (ascorbic acid) → scurvy; D → rickets; K → bleeding tendency.
- Enzymes: proteins (some RNA = ribozymes) that catalyse a specific reaction at an active site; one enzyme per substrate; cofactors/coenzymes help activity; heat/pH denature them.
Enzyme naming
MCQ Questions
Lipids, Hormones and Everyday Relevance
Lipids
Oils, fats and waxes — esters of long-chain acids with glycerol (triglycerides). They insulate, store energy and form membranes (phospholipids); oxidation of fats yields the most energy per gram among biomolecules.
- Hormones: chemical messengers — insulin (lowers glucose), adrenaline (fight-or-flight), thyroxine (metabolism), testosterone/oestrogen (reproductive).
- Vitamins flags, enzymes run metabolism, nucleic acids instruct, carbohydrates fuel — the same molecules you studied all connect.
- Everyday: instant glucose drinks, sports electrolytes, vitamin tablets, insulin pens, protein supplements — all biomolecule chemistry in practice.
Chapter link
MCQ Questions
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q1–Q3)
- 1What are the products of hydrolysis of lactose?
- 2Write the structure of the zwitterionic form of alanine at pH 7.
- 3Name the four bases present in DNA. Which one is not present in RNA?
Answers at a glance
- 1D‑Glucose and D‑galactose.
- 2+H3N‑CH(CH3)‑COO–
- 3A, G, C, T; thymine is absent in RNA (uracil takes its place).
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1What are monosaccharides?
- 2Define glycosidic linkage.
- 3Name the disease caused by deficiency of vitamin C.
2 Mark Questions
- 1Differentiate between fibrous and globular proteins.
- 2What is the biological significance of sucrose?
3 Mark Questions
- 1Explain the mechanism of enzyme action.
- 2Describe the primary, secondary, tertiary and quaternary structure of proteins.
5 Mark Questions
- 1Describe the process of transcription in molecular biology.
- 2Explain the following: (i) Why is cellulose not digested by humans? (ii) How does the structure of DNA help in its replication?
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Class 12 Chemistry — downloadable assignments and CBSE-pattern tests (PDF).
Topic-wise practice covering the first half of the chapter, with answer key.
Topic-wise practice covering the second half of the chapter, with answer key.
Full CBSE-pattern test (90 minutes, 40 marks) with answer key.
Second full CBSE-pattern test (90 minutes, 40 marks) with answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Glucose
An aldohexose.
Sucrose
α-D-glucose + β-D-fructose (glycosidic bond).
Peptide bond
Links amino acids; formed by condensation.
Chargaff base pair
DNA; A-U (uracil) replaces T in RNA.
Specific rotation
Mutarotation of glucose is a change in [α]D.
Zwitterion
Amino acids at the isoelectric point.
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- Carbohydrate classification: monosaccharides (glucose, fructose), disaccharides (sucrose, maltose, lactose), polysaccharides (starch, cellulose, glycogen).
- Glucose structure: open chain (aldehyde) vs cyclic pyranose; α‑/β‑anomers; Haworth projection + mutarotation.
- Reducing vs non-reducing sugars — sucrose non-reducing because both anomeric carbons are linked.
- Tests: Tollen's/Benedict's for reducing sugars; invert sugar when sucrose hydrolyses.
- Amino acids: α‑structure, essential vs non-essential, zwitterion/amphoteric, isoelectric point.
- Protein structure levels: primary → secondary (α-helix, β-sheet) → tertiary → quaternary; denaturation.
- Nucleic acids: nucleotide vs nucleoside; DNA double helix with A‑T/G‑C pairs; RNA types (mRNA, tRNA, rRNA).
- Enzymes: specificity, active site, cofactors/coenzymes; denaturation by heat/pH.
- Vitamins: fat- vs water-soluble; deficiency diseases (A–night blindness, B1–beriberi, C–scurvy, D–rickets).
- Lipids (fats/oils/waxes, triglycerides), hormones and their functions.
Practice Numericals
Step-by-step worked examples
Standard exam-level problems solved with clear conceptual breakdowns.
Reducing vs non-reducing
Step-by-Step Solution
- 1Maltose = two glucose units joined so one anomeric carbon is free.
- 2Its free hemiacetal opens to an aldehyde → reduces Fehling's.
- 3Sucrose joins C₁ of glucose to C₂ of fructose — both locked.
Final Answer
Maltose is reducing; sucrose is not.
Counting ATP from glucose
Step-by-Step Solution
- 1C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy.
- 2This is why reducing sugar tests depend on the aldehyde, not the energy yield — keep them separate.
Final Answer
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ~38 ATP.
FAQ
Frequently asked questions
What is mutarotation and why does glucose show it?
Fresh crystals of α-D-glucose give a specific rotation of +112°, β-D-glucose +18.7°, but either solution in water slowly settles at +52.7°. The two anomers interconvert through the open-chain aldehyde form, changing rotation until equilibrium — that's mutarotation. The open form is also why glucose is a reducing sugar.
How do sugars and proteins give their colour tests?
Tollen's reagent (ammoniacal silver nitrate) and Benedict's/Fehling's (alkaline Cu²⁺) both oxidise the free aldehyde of a reducing sugar — a silver mirror or brick-red Cu₂O appears. Ninhydrin turns α-amino acids (and proteins) blue-purple by reacting with the free amino group; biuret's violet colour comes from peptide bonds. The two families are distinguished cleanly by these.
Why is an α-amino acid zwitterionic?
The molecule carries one acidic (–COOH) and one basic (–NH₂) group. In water the acid donates a proton to the base: –NH₃⁺ and –COO⁻ coexist. The zwitterion is neutral overall yet highly polar, which explains high melting points and water solubility. At the isoelectric pH, both forms are balanced and the amino acid does not migrate in an electric field.
What exactly differs between DNA and RNA?
Sugar: DNA has 2‑deoxyribose, RNA ribose (one extra –OH). Base: DNA uses thymine, RNA uses uracil. Shape: DNA is a double helix with A‑T and G‑C pairs; RNA is mostly single-stranded. Function: DNA stores genetic information; RNA transmits it — mRNA carries the message, tRNA ferries amino acids, rRNA builds the ribosome.
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