Class 11 Maths Notes
~10 min readComplex Numbers Class 11 Notes
Complete, exam-ready notes on complex numbers: the imaginary unit i, the form z = a + ib, addition, subtraction, multiplication and division, conjugates and moduli, the Argand plane and polar form, quadratic equations with real coefficients, and cube roots of unity — written for CBSE, JEE and NEET revision.
What is this chapter about in one line?
Complex numbers extend the real number line to a plane using the imaginary unit i, giving solutions to every quadratic and rich tools like modulus and polar form.
The Imaginary Unit and Standard Form
Imaginary unit i and complex number z = a + ib
The imaginary unit i satisfies i² = −1. A complex number is written z = a + ib, where a is the real part Re(z) and b is the imaginary part Im(z). Real numbers are the case b = 0; pure imaginary numbers have a = 0.
- Powers of i cycle in fours: i¹ = i, i² = −1, i³ = −i, i⁴ = 1.
- Two complex numbers are equal iff their real and imaginary parts are equal.
- Zero in complex form is 0 + 0i.
Addition, Subtraction, Multiplication and Division
Operations on complex numbers
Add or subtract like terms: add real to real and imaginary to imaginary. Multiply by expanding (foil), using i² = −1. Divide by multiplying numerator and denominator by the conjugate of the denominator to make it real.
- Addition: (a + ib) + (c + id) = (a + c) + i(b + d).
- Multiplication: (a + ib)(c + id) = (ac − bd) + i(ad + bc).
- Division: (a + ib)/(c + id) = (a + ib)(c − id)/(c² + d²).
Conjugate and Modulus
Conjugate z̄ and modulus |z|
The conjugate of z = a + ib is z̄ = a − ib; geometrically it reflects z across the real axis. The modulus |z| is the distance of z from the origin in the Argand plane. Multiplying a number by its conjugate gives the square of its modulus.
Argand Plane and Polar Form
Argand plane and polar form
In the Argand plane, the real part is the x-axis and the imaginary part the y-axis. Polar form writes z = r(cosθ + i sinθ) where r = |z| is the modulus and θ the argument, the angle the vector makes with the positive real axis.
Product of moduli
Quadratic Equations with Complex Roots
Quadratic with real coefficients
A quadratic ax² + bx + c = 0 with real coefficients has complex (non-real) roots exactly when its discriminant is negative. Such roots always appear as a conjugate pair a ± ib.
- Discriminant D = b² − 4ac; if D < 0 the roots are complex conjugates.
- Roots: x = (−b ± √(b² − 4ac))/(2a), using i for the square root of a negative number.
- Sum of roots = −b/a and product = c/a for any quadratic.
Cube Roots of Unity
Cube roots of unity
The three cube roots of 1 are 1, ω and ω². They always satisfy ω³ = 1 and 1 + ω + ω² = 0, and they lie at the vertices of an equilateral triangle in the Argand plane.
Simplify high powers
Solved Examples
Example: Find the conjugate and modulus of z = 3 + 4i, and compute z·z̄.
Solution: z̄ = 3 − 4i; |z| = √(9 + 16) = 5; z·z̄ = 9 + 16 = 25 = |z|².
Example: Write z = 1 + i in polar form.
Solution: r = √(1 + 1) = √2 and θ = tan⁻¹(1/1) = π/4, so z = √2(cos(π/4) + i sin(π/4)).
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q1–Q14)
- 1) Express the complex number (5i)(−3/5 i) in the form a + ib.
- 2) Express the complex number i⁹ + i¹⁹ in the form a + ib.
- 3) Express the complex number i⁻³⁹ in the form a + ib.
- 4) Express the complex number 3(7 + 7i) + i(7 + 7i) in the form a + ib.
- 5) Express the complex number (1 − i) − (−1 + 6i) in the form a + ib.
- 6) Express the complex number (1/5 + 2/5 i) − (4 + 5/2 i) in the form a + ib.
- 7) Express the complex number [(1/3 + 7/3 i) + (4 + 1/3 i)] − (−4/3 + i) in the form a + ib.
- 8) Express the complex number (1 − i)⁴ in the form a + ib.
- 9) Express the complex number (1/3 + 3i)³ in the form a + ib.
- 10) Express the complex number (−2 − 1/3 i)³ in the form a + ib.
- 11) Find the multiplicative inverse of the complex number 4 − 3i.
- 12) Find the multiplicative inverse of the complex number √5 + 3i.
- 13) Find the multiplicative inverse of the complex number −i.
- 14) Express the expression (3 + i√5)(3 − i√5) / [(√3 + √2 i) − (√3 − √2 i)] in the form a + ib.
Answers at a glance
- 1Q1 → 3 + 0i.
- 2Q2 → 0 + 0i.
- 3Q3 → 0 + i.
- 4Q4 → 14 + 28i.
- 5Q5 → 2 − 7i.
- 6Q6 → −19/5 − 21/10 i.
- 7Q7 → 17/3 + 5/3 i.
- 8Q8 → −4 + 0i.
- 9Q9 → −242/27 − 26i.
- 10Q10 → −22/3 − 107/27 i.
- 11Q11 → 4/25 + 3/25 i.
- 12Q12 → √5/14 − 3/14 i.
- 13Q13 → i.
- 14Q14 → 0 − (7/√2)i.
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1Find the modulus of −2i. (Ans: 2)
- 2Write i⁴. (Ans: 1)
- 3State the condition for two complex numbers to be equal.
- 4Find the conjugate of 5 + 2i. (Ans: 5 − 2i)
2 Mark Questions
- 1Express (2 + 3i)(1 − i) in the form a + ib. (Ans: 5 + i)
- 2Find the real and imaginary parts of (1 + 2i)/(1 − i). (Ans: multiply by conjugate: (−1 + 3i)/2, real −1/2, imaginary 3/2)
- 3Find (1 + i)² and write its modulus. (Ans: 2i, modulus 2)
3 Mark Questions
- 1Find the multiplicative inverse of 1 − i. (Ans: (1 + i)/2 = 1/2 + (1/2)i)
- 2Write 1 + √3 i in polar form. (Ans: r = 2, θ = π/3, so 2(cos π/3 + i sin π/3))
- 3Solve x² + 2 = 0 over C. (Ans: x = ±√2 i)
4 Mark Questions
- 1Derive the formula for the square root of a complex number a + ib and use it to find √(7 + 24i). (Ans: ±(4 + 3i))
- 2Find the modulus and argument of (1 + i)/(1 − i), and write the result in polar form. (Ans: (−1)²+... result is i; modulus 1, argument π/2)
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Practice path: complete Assignment 1 first (topic-by-topic), then Assignment 2 (mixed difficulty with full solutions), then attempt the timed tests.
Covers all six topics: the imaginary unit and standard form; addition, subtraction, multiplication and division; conjugate and modulus; Argand plane and polar form; quadratic equations with complex roots; and cube roots of unity.
Higher-difficulty set with multi-step problems (powers of i, division in a + ib form, modulus/argument of quotients, polar conversion, complex quadratic roots, ω identities) and full worked answers. Includes an answer key.
Full board-pattern test: Section A (MCQ/VSA 1M × 10), Section B (2M × 4), Section C (3M × 4), Section D (5M × 2) = 40 marks. Time: 90 minutes. Includes answer key.
Second full paper with different questions, same 40-mark / 90-minute blueprint. Includes answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Imaginary unit
Conjugate squared
Product of moduli
Conjugate
Modulus
Polar form
Cube roots of unity
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- i² = −1; powers of i cycle through i, −1, −i, 1.
- Two complex numbers are equal iff real parts and imaginary parts match.
- Divide by multiplying the top and bottom by the conjugate.
- The modulus |z| = √(a² + b²) is the distance from the origin.
- z·z̄ = |z|² is handy for dividing and simplifying.
- Polar form z = r(cosθ + i sinθ) simplifies products and powers.
- Cube roots of unity: 1 + ω + ω² = 0 and ω³ = 1.
FAQ
Frequently asked questions
What is the imaginary unit i?
i is defined by i² = −1. Any complex number is written z = a + ib, with a the real part and b the imaginary part.
How do you divide two complex numbers?
Multiply both numerator and denominator by the conjugate of the denominator. For (a + ib)/(c + id), this gives (a + ib)(c − id)/(c² + d²), making the denominator a real number.
What are the conjugate and modulus of a complex number?
The conjugate of a + ib is a − ib. The modulus is |z| = √(a² + b²), the distance from the origin. Their product z·z̄ = |z|² is always a non-negative real number.
What are the cube roots of unity?
The three cube roots of 1 are 1, ω and ω². They satisfy ω³ = 1 and 1 + ω + ω² = 0, and they are placed at the vertices of an equilateral triangle in the Argand plane.
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