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Class 12 Maths Notes

Continuity and Differentiability Class 12 Notes

Complete, exam-ready notes on continuity and differentiability: the limit definition of continuity, differentiability and its link to continuity, the standard differentiation rules, and logarithmic, implicit and parametric differentiation — written for CBSE boards and JEE revision.

Class12SubjectMathematicsCoversCBSE · JEE

Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali

What is this chapter about in one line?

Continuity and Differentiability studies when a function's graph has no breaks (continuous) and when it has a well-defined slope (differentiable) — the foundation of all calculus in Class 12.

Continuity of a Function

Continuity at a point

limxaf(x)=f(a)\lim_{x\to a}f(x) = f(a)

A function is continuous at x = a when it is defined at a, the limit exists at a, and the two are equal. All polynomial, rational, trigonometric, exponential and logarithmic functions are continuous on their domains.

  • Left-hand limit and right-hand limit must both equal f(a).
  • Sums, differences, products and quotients (with non-zero denominator) of continuous functions are continuous.
  • A common composite rule:
  • limxaf(g(x))=f(limxag(x))\lim_{x\to a} f(g(x)) = f\left(\lim_{x\to a} g(x)\right)
  • when f is continuous.

Classic trap: |x| at 0

The absolute value function is continuous at x = 0 but NOT differentiable there — the left and right slopes differ. Continuity does not guarantee differentiability.

Differentiability

Derivative at a point

f(a)=limh0f(a+h)f(a)hf'(a) = \lim_{h\to 0}\frac{f(a+h) - f(a)}{h}

The derivative is the slope of the tangent, or the limit of the secant slope. Differentiability at a point implies continuity there, but the converse is false.

  • A function is differentiable on an open interval if it is differentiable at every point of it.
  • If the left and right derivatives differ, the function is not differentiable (a sharp corner).
  • Standard derivatives:
  • ddxxn=nxn1\frac{d}{dx}x^n = nx^{n-1}
  • ,
  • ddxsinx=cosx\frac{d}{dx}\sin x = \cos x
  • ,
  • ddxex=ex\frac{d}{dx}e^x = e^x
  • .
f(a)=limh0f(a+h)f(a)hf'(a) = \lim_{h\to 0}\frac{f(a+h)-f(a)}{h}
Definition of the derivative

Rules of Differentiation

  • Chain rule:
  • dydx=dydududx\frac{dy}{dx} = \frac{dy}{du}\frac{du}{dx}
  • .
  • Product rule:
  • (uv)=uv+uv(uv)' = u'v + uv'
  • .
  • Quotient rule:
  • (uv)=uvuvv2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}
  • .
  • Derivatives of inverse trig functions and the special forms
  • ddxlnx=1x\frac{d}{dx}\ln x = \frac{1}{x}
  • ,
  • ddxax=axlna\frac{d}{dx}a^x = a^x\ln a
  • .
dydx=dydududx,(uv)=uv+uv\frac{dy}{dx} = \frac{dy}{du}\frac{du}{dx},\quad (uv)' = u'v + uv'
Chain and product rules

Logarithmic, Implicit and Parametric Differentiation

  • Logarithmic differentiation: take ln of both sides first, then differentiate — ideal for
  • xxx^x
  • or long products and powers.
  • Implicit differentiation: differentiate y(x) terms using the chain rule, then solve for
  • dy/dxdy/dx
  • .
  • Parametric form: if
  • x=f(t)x = f(t)
  • ,
  • y=g(t)y = g(t)
  • then
  • dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}
  • .
  • The second derivative in parametric form:
  • d2ydx2=ddt(dydx)/dxdt\frac{d^2y}{dx^2} = \frac{d}{dt}\left(\frac{dy}{dx}\right)\Big/\frac{dx}{dt}
  • (with care about the chain rule).
dydx=dy/dtdx/dt,ddx(lny)=1ydydx\frac{dy}{dx} = \frac{dy/dt}{dx/dt},\quad \frac{d}{dx}(\ln y) = \frac{1}{y}\frac{dy}{dx}
Parametric and logarithmic differentiation

Solved Examples

Example: Find dydx\frac{dy}{dx} if y=sin(x2+1)y = \sin(x^2 + 1).

Solution: Using the chain rule with u=x2+1u = x^2 + 1: dydx=cos(x2+1)2x=2xcos(x2+1)\frac{dy}{dx} = \cos(x^2+1) \cdot 2x = 2x\cos(x^2+1).

Revision

Key formulas at a glance

Memorise these before attempting numericals — most exam questions hinge on one of them.

Continuity

limxaf(x)=f(a)\lim_{x\to a}f(x) = f(a)

Derivative definition

f(a)=limh0f(a+h)f(a)hf'(a) = \lim_{h\to 0}\frac{f(a+h)-f(a)}{h}

Chain rule

dydx=dydududx\frac{dy}{dx} = \frac{dy}{du}\frac{du}{dx}

Product rule

(uv)=uv+uv(uv)' = u'v + uv'

Quotient rule

(uv)=uvuvv2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}

Parametric form

dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}

Power rule

ddxxn=nxn1\frac{d}{dx}x^n = nx^{n-1}

Exam tips

How this chapter is asked

Where this topic appears in CBSE, JEE Main and NEET papers.

  • Differentiability implies continuity, but not vice versa.
  • A sharp corner (like |x| at 0) is continuous but not differentiable.
  • Check continuity via LHL and RHL separately.
  • Use the chain rule whenever a function is composed, even implicitly.
  • Logarithmic differentiation handles x^x and products of many factors.
  • Parametric slope = (dy/dt)/(dx/dt).

FAQ

Common questions

Does continuity imply differentiability?

No. Continuity at a point only guarantees the limit equals the function value. A function like |x| is continuous but not differentiable at x = 0 because the left and right slopes differ.

How do I check if a function is continuous at a point?

Verify the function is defined there, the left-hand and right-hand limits both exist and agree, and their common value equals f(a).

When is logarithmic differentiation used?

For expressions like x^x, or a product of many factors, taking ln on both sides converts products into sums before differentiating — much simpler.

What does parametric differentiation mean?

When x and y are both given in terms of a parameter t, the slope is dy/dx = (dy/dt)/(dx/dt) rather than a direct derivative of y with respect to x.

Mastering this chapter with live help

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