Class 12 Physics Notes
~9 min readDual Nature of Radiation and Matter Class 12 Notes
Complete, exam-ready notes on the dual nature of radiation and matter: the photoelectric effect and its laws, Einstein's photoelectric equation, stopping potential graphs, de Broglie waves and the Davisson-Germer experiment — written for CBSE boards, JEE and NEET revision.
What is the dual nature of radiation and matter in one line?
Light behaves as waves in some experiments (interference, diffraction) and as particles of energy E = hν in others (photoelectric effect), and matter particles also have an associated wave of wavelength λ = h/p.
Photoelectric Effect
Photoelectric effect
The emission of electrons from a metal surface when light of high enough frequency shines on it. Discovered experimentally by Hertz (1887), with key observations by Lenard, and explained by Einstein in 1905.
- For a given metal there is a threshold frequency
- below which no electrons are emitted, however intense the light.
- The maximum kinetic energy of emitted electrons depends on the frequency, not the intensity, of light.
- The number of emitted electrons per second (the photocurrent) is proportional to the intensity.
- Emission is nearly instantaneous — there is no meaningful time lag.
Wave theory fails here
Einstein's Photoelectric Equation
Work function
The minimum energy needed to free an electron from the metal surface. A photon of energy supplies this work function and the remainder appears as the electron's maximum kinetic energy .
- Photon energy:
- .
- Photon momentum:
- .
- Above the threshold:
- ; below it no current flows at any intensity.
Stopping Potential and Graphs
Stopping potential
The reverse voltage that just stops the fastest photoelectrons: . A graph of against frequency ν is a straight line of slope (universal, independent of the metal) that cuts the frequency axis at the threshold .
- Slope of the V₀–ν graph:
- .
- Different metals give parallel lines with the same slope but different intercepts (work functions).
- The saturation photocurrent rises with intensity at fixed frequency.
Wave Nature of Matter — de Broglie
de Broglie wavelength
Matter has a wave nature: a particle of momentum p has an associated wavelength . For an electron accelerated through potential V: .
- Heavy or fast objects have tiny wavelengths — that is why macroscopic matter shows no observable wave behaviour.
- Increasing the accelerating voltage decreases the electron wavelength.
- Momentum of a photon can also be written
- .
Davisson-Germer Experiment
Davisson-Germer
Electrons fired at a nickel crystal and scattered at a specific angle produced a strong reflected beam — a diffraction pattern that matched the de Broglie wavelength, giving the first direct experimental confirmation of electron waves (1927).
- The effect appears only for certain accelerating voltages, where the de Broglie wavelength satisfies the diffraction condition.
- It confirms the wave nature of matter and completes the particle–wave duality of electrons.
Solved Examples
Example: A metal has a work function of 2.0 eV. Light of wavelength 400 nm falls on it. Find the maximum kinetic energy of the emitted electrons.
Solution: Photon energy . Then . The electrons are released, so the photoelectric effect occurs.
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q11.1–Q11.11)
- 11.1) Find the (a) maximum frequency, and (b) minimum wavelength of X-rays produced by 30 kV electrons.
- 11.2) The work function of caesium metal is 2.14 eV. When light of frequency 6 × 10¹⁴ Hz is incident on the metal surface, photoemission of electrons occurs. What is the (a) maximum kinetic energy of the emitted electrons, (b) stopping potential, and (c) maximum speed of the emitted photoelectrons?
- 11.3) The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
- 11.4) Monochromatic light of wavelength 632.8 nm is produced by a helium-neon laser. The power emitted is 9.42 mW. (a) Find the energy and momentum of each photon in the light beam, (b) How many photons per second, on the average, arrive at a target irradiated by this beam? (Assume the beam to have uniform cross-section which is less than the target area), and (c) How fast does a hydrogen atom have to travel in order to have the same momentum as that of the photon?
- 11.5) In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10⁻¹⁵ V s. Calculate the value of Planck's constant.
- 11.6) The threshold frequency for a certain metal is 3.3 × 10¹⁴ Hz. If light of frequency 8.2 × 10¹⁴ Hz is incident on the metal, predict the cut-off voltage for the photoelectric emission.
- 11.7) The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?
- 11.8) Light of frequency 7.21 × 10¹⁴ Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 × 10⁵ m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?
- 11.9) Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.
- 11.10) What is the de Broglie wavelength of (a) a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s, (b) a ball of mass 0.060 kg moving at a speed of 1.0 m/s, and (c) a dust particle of mass 1.0 × 10⁻⁹ kg drifting with a speed of 2.2 m/s?
- 11.11) Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).
Answers at a glance
- 1Q11.1 → (a) ν_max = 7.24 × 10¹⁸ Hz. (b) λ_min = 4.14 × 10⁻¹¹ m.
- 2Q11.2 → (a) K_max = 0.346 eV (0.35 eV). (b) V₀ = 0.35 V. (c) v_max = 3.49 × 10⁵ m/s.
- 3Q11.3 → K_max = 1.5 eV = 2.4 × 10⁻¹⁹ J.
- 4Q11.4 → (a) E = 3.14 × 10⁻¹⁹ J (1.96 eV), p = 1.05 × 10⁻²⁷ kg m s⁻¹. (b) 3.0 × 10¹⁶ photons/s. (c) v = 0.63 m/s.
- 5Q11.5 → h = 6.6 × 10⁻³⁴ J s.
- 6Q11.6 → V₀ = 2.03 V.
- 7Q11.7 → No — the photon energy (3.77 eV) is less than the work function (4.2 eV).
- 8Q11.8 → ν₀ = 4.74 × 10¹⁴ Hz.
- 9Q11.9 → φ₀ = 2.17 eV.
- 10Q11.10 → (a) 1.66 × 10⁻³⁵ m. (b) 1.11 × 10⁻³² m. (c) 3.01 × 10⁻²⁵ m.
- 11Q11.11 → λ_EM = h/p = λ_dB, since the photon's momentum is p = h/λ.
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1State the de Broglie relation for the wavelength of a moving particle.
- 2Define the work function of a metal.
- 3On what does the maximum kinetic energy of emitted photoelectrons depend?
- 4Define the stopping potential for a given metal and frequency of incident light.
2 Mark Questions
- 1Calculate the de Broglie wavelength of an electron accelerated through a potential difference of 100 V. (Ans: λ = 12.27/√V Å = 1.227 Å)
- 2The work function of a metal is 2 eV. Find its threshold frequency. (Ans: ν₀ = W₀/h ≈ 4.8 × 10¹⁴ Hz)
- 3Light of frequency 7.5 × 10¹⁴ Hz is incident on a metal of work function 2 eV. Find the maximum kinetic energy of the photoelectrons. (Ans: Kmax = hν − W₀ ≈ 1.1 eV)
3 Mark Questions
- 1State and explain the laws of photoelectric emission, and give the experimental arrangement used to study them.
- 2Derive Einstein's photoelectric equation hν = W₀ + ½mv² and explain the concept of threshold frequency.
- 3Draw the stopping potential versus frequency graph for a metal and explain how its slope and intercept determine h/e and the work function. (Ans: slope = h/e, intercept = W₀/e)
5 Mark Questions
- 1Describe the experimental study of the photoelectric effect (apparatus, observations, graphs of photocurrent versus potential and versus intensity) and explain why the wave theory of light fails to account for it while Einstein's photon picture succeeds.
- 2Derive the de Broglie wavelength of an electron accelerated through a potential V and hence show that matter shows wave–particle duality; account for why wave nature was observed for electrons but not for macroscopic bodies.
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Practice path: complete Assignment 1 first (topic-by-topic), then Assignment 2 (mixed difficulty with full solutions), then attempt the timed tests.
Covers all five topics: photoelectric effect; Einstein's photoelectric equation; stopping potential and graphs; wave nature of matter (de Broglie); and the Davisson-Germer experiment. Arranged topic by topic.
Higher-difficulty set with multi-topic integration problems (work function and threshold, Einstein's equation, K_max–ν graphs, de Broglie wavelength of accelerated electrons) and full worked answers. Includes an answer key.
Full board-pattern test: Section A (MCQ/VSA 1M × 10), Section B (2M × 4), Section C (3M × 4), Section D (5M × 2) = 40 marks. Time: 90 minutes. Includes answer key.
Second full paper with different questions, same 40-mark / 90-minute blueprint. Includes answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Photon energy
Einstein's equation
Stopping potential
de Broglie wavelength
Electron wavelength
Photoelectric threshold
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- Photocurrent depends on intensity; K_max depends on frequency — never mix the two.
- Below the threshold frequency, no photoelectrons at any intensity.
- The V₀–ν graph has universal slope h/e.
- λ = h/p; an electron accelerated by V has λ = 12.27/√V Å.
- Davisson-Germer confirmed the wave nature of electrons.
- Work function is metal-specific; 1 eV = 1.6 × 10⁻¹⁹ J.
FAQ
Frequently asked questions
Does increasing light intensity increase the energy of photoelectrons?
No. Intensity increases the number of photoelectrons (the current), not their energy. The maximum kinetic energy depends only on the frequency of light and the metal's work function.
What happens if light frequency is below the threshold?
No electrons are emitted at all, no matter how intense or how long the light shines, because each photon carries less energy than the work function.
What is the work function of a metal?
It is the minimum energy required to remove an electron from the surface, equal to hν₀ where ν₀ is the threshold frequency.
Why don't we see wave behaviour in everyday objects?
A cricket ball has a huge momentum, so its de Broglie wavelength λ = h/p is absurdly small — far below any measurable scale. Wave behaviour is observable only for microscopic particles.
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