Class 12 Chemistry Notes
~8 min readInorganic Chemistry Class 12 Notes
Complete, exam-ready notes on inorganic chemistry for Class 12: p-block and d-block elements, f-block (lanthanides and actinides), coordination compounds and crystal field theory — written for CBSE boards, JEE and NEET revision.
What is inorganic chemistry in one line?
Inorganic chemistry is the study of the properties and reactions of the elements (except carbon compounds) — including p-block, d-block and f-block elements, and coordination compounds.
p-Block Elements
- Group 15 (N, P, As, Sb, Bi): nitrogen is a gas, P and As solids; hydrides NH₃, PH₃, etc. Ammonia is the strongest base.
- Group 16 (O, S, Se, Te): ozone O₃ is an allotrope; sulphur forms many allotropes (rhombic, monoclinic); H₂SO₄ is a strong dibasic acid.
- Group 17 (halogens): reactivity decreases down the group; fluorine is the most electronegative element.
- Group 18 (noble gases): chemically inert, with Xe forming stable compounds with F and O (e.g. XeF₂, XeF₄).
Key anomalies
d-Block (Transition) Elements
Transition element
An element with a partially filled d-orbital in its ion or ground state. They show variable oxidation states, form coloured ions and complexes, and are useful catalysts.
- Variable oxidation states — e.g. Mn shows +2 to +7.
- Colour arises from d-d transitions.
- Magnetic properties from unpaired d-electrons.
- Catalytic activity: Fe in Haber process, V₂O₅ in contact process, Ni in hydrogenation.
- High melting points due to strong metallic bonding from d-electrons.
Sc and Zn are not typical transition elements
f-Block Elements (Lanthanides and Actinides)
- Lanthanides (Ce–Lu): show +3 oxidation state predominantly, lanthanide contraction (steady decrease in ionic radius with atomic number).
- Actinides (Th–Lr): radioactive, show variable oxidation states.
- Lanthanide contraction arises because the 4f electrons poorly shield the increasing nuclear charge.
- Uses: mischmetal in lighter flints, lanthanides in magnets and phosphors.
Coordination Compounds
Coordination compound
A complex formed by a central metal ion (M) bonded to ligands (L). The coordination number is the number of donor atoms bonded to the metal. Common geometries: tetrahedral (4), square planar (4), octahedral (6).
Crystal field theory (CFT)
Ligands create a crystal field that splits the degenerate d-orbitals into t₂g (lower energy) and e_g (higher energy) sets in octahedral complexes. The splitting energy is .
- Strong-field ligands (CN⁻, CO) cause large Δo and give low-spin complexes.
- Weak-field ligands (Cl⁻, H₂O) cause small Δo and give high-spin complexes.
- Spectrochemical series:
- .
- Werner's theory explained primary (ionisable) vs secondary (coordination) valence.
Isomerism in Coordination Compounds
- Geometrical (cis/trans) — depends on arrangement of ligands.
- Optical (d/l) — non-superimposable mirror images.
- Linkage isomerism — ligand binds through different donor atoms (e.g. -NO₂ vs -ONO).
- Ionisation isomerism — different ions in the coordination sphere vs solution.
- Coordination isomerism — exchange of ligands between cationic and anionic complexes.
Qualitative and Quantitative Analysis
Inorganic qualitative analysis uses group reagents to precipitate cations: H₂S, NH₄OH and (NH₄)₂S separate ions into groups. Volumetric analysis includes redox titrations (KMnO₄, K₂Cr₂O₇) and gravimetric methods.
- Cation group separation based on solubility products of sulphides and hydroxides.
- Confirmatory tests: flame test, borax bead test, sodium carbonate extract tests.
- Redox titrations: self-indicating KMnO₄ (pink) and K₂Cr₂O₇ with diphenylamine indicator.
Solved Examples
Example: Find the oxidation state of Cr in .
Solution: NH₃ is neutral, Cl is -1 (two Cl = -2), overall charge +1, so . Cr is in the +3 oxidation state.
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q1–Q2)
- 1) Q1. Exercise question 1
- 2) Q2. Exercise question 2
Answers at a glance
- 1Q1 → Answer 1
- 2Q2 → Answer 2
CBSE Pattern Questions
Board mapping
MCQ Questions
1 Mark Questions
- Q1 (1M)
- Q2 (1M)
- Q3 (1M)
- Q4 (1M)
2 Mark Questions
- Q1 (2M)
- Q2 (2M)
- Q3 (2M)
3 Mark Questions
- Q1 (3M)
- Q2 (3M)
- Q3 (3M)
5 Mark Questions
- Q1 (5M)
- Q2 (5M)
PDF: Assignments & Tests
Printable study material
Assignments walk the chapter's topics in order; the tests follow the current CBSE blueprint (MCQ/VSA, 2M, 3M and 5M questions) with answer keys. They will appear here as direct download links.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Spectrochemical series
CFT splitting (octahedral)
Coordination compound
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- Sc and Zn are not typical transition elements.
- Strong-field ligands form low-spin complexes.
- Lanthanide contraction explains similar properties across the series.
- Spectrochemical series predicts field strength and spin state.
- NH₃ is neutral, so oxidation state of Cr in [Cr(NH₃)₄Cl₂]+ is +3.
FAQ
Frequently asked questions
What is the spectrochemical series?
It is a ranking of ligands by the magnitude of crystal-field splitting they cause: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO. CN⁻ and CO are strong-field ligands.
Why do transition metals form coloured compounds?
Because of d-d electronic transitions between split d-orbitals, which absorb visible light. This is why ions like Cu²⁺ and Cr³⁺ appear coloured.
What is the difference between high-spin and low-spin complexes?
Weak-field ligands (small Δo) give high-spin complexes where electrons fill d-orbitals singly; strong-field ligands (large Δo) give low-spin complexes where electrons pair in lower-energy t₂g orbitals.
What is lanthanide contraction?
The steady decrease in ionic radius across the lanthanide series due to the poor shielding of 4f electrons. It causes chemical similarity across consecutive lanthanides.
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