Class 12 Maths Notes
Complete, exam-ready notes on linear programming: formulating an LPP from a word problem, drawing the feasible region, and using the corner point method to maximise profit or minimise cost — written for CBSE boards and JEE revision.
Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali
Linear programming optimises a linear objective under linear constraints, and the optimum always sits at a corner of the feasible region.
An LPP has a linear objective function to maximise or minimise, subject to linear constraints like and non-negativity . The feasible region is the set of points satisfying every constraint.
Corners are enough
You never need to test interior points: the linear objective is maximised or minimised at a corner of the feasible region. Evaluate Z only at the vertices.
Example: Maximise subject to , , .
Solution: The feasible region has corners (0,0), (2,0), (3,1), (0,4). Evaluating Z: 0, 6, 11 and 8. The maximum is 11 at (3,1).
Example: A machine makes two items A and B with a profit of ₹50 and ₹80, and takes 4 and 6 hours per unit with 60 hours available. Maximise daily profit.
Solution: subject to , . Corners give (0,0)=0, (15,0)=750, (0,10)=800, so 10 units of B alone maximise profit at ₹800.
Revision
Memorise these before attempting numericals — most exam questions hinge on one of them.
Objective function
Feasibility
Corner point rule
Line from intercepts
Exam tips
Where this topic appears in CBSE, JEE Main and NEET papers.
FAQ
The objective Z = ax + by is a family of parallel lines; the feasible region is a convex polygon. Sliding these lines, the last feasible line always touches a vertex, so the max and min occur at corners.
The set of all points satisfying every constraint, including non-negativity. Only points inside it are possible solutions the company can actually implement.
The problem may still have an optimum, but a maximisation can be unbounded if Z grows without bound in an open direction — the graph tells you whether the region is closed in the direction of increase.
Yes. If the objective line runs parallel to an edge of the feasible region, that entire edge is optimal, giving infinitely many solutions with the same value of Z.
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