Class 11 Chemistry Notes
Complete, exam-ready notes on the basics of organic chemistry: why carbon is special, IUPAC nomenclature, functional groups, structural and stereoisomerism, hybridisation, electron displacement effects like inductive and resonance, reactive intermediates, and the main types of organic reactions — written for CBSE, JEE and NEET revision.
Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali
Carbon forms four covalent bonds (tetravalency) and joins into long chains and rings (catenation) with remarkable strength, giving millions of stable compounds.
Name in steps: find the longest parent chain (root: meth, eth, prop, but, pent...), number it to give substituents the lowest locants, add the functional group suffix (-ol, -al, -one, -oic acid) and locate double/triple bonds with -ene/-yne.
A functional group is the atom or bond that gives a family its characteristic reactions — alcohols (OH), aldehydes (–CHO), ketones (–C=O), carboxylic acids (–COOH), amines (–NH₂), halides (X), nitriles (–CN).The same group gives a family similar chemistry, so classification follows the functional group.
Structural isomers share a formula but differ in connectivity — chain (n-butane/isobutane), position (1-propanol/2-propanol), functional (ethanol/dimethyl ether) and tautomerism.
Sigma-bond polarisation pulls electron density along a chain. Electron-withdrawing groups (−I): F, Cl, NO₂, CN, CF₃. Electron-donating groups (+I): alkyl groups. The effect weakens sharply with distance.
Delocalised electrons spread over several atoms, stabilising the molecule. Carboxylate and nitrate ions and benzene are resonance stabilised. The mesomeric effect (M) acts through π systems.
Short-lived species formed during reactions. Carbocation stability: 3° > 2° > 1° > methyl (hyperconjugation + inductive). Carbanion stability is the reverse. Free radicals are neutral with an unpaired electron.
Example: Name CH₃CH(CH₃)CH₂CH₃ by IUPAC rules.
Solution: Longest chain has four carbons → butane; the methyl substituent is on carbon 2 → 2-methylbutane.
Example: Why is the tertiary carbocation most stable?
Solution: More alkyl groups donate electron density through the +I effect and hyperconjugation, spreading and stabilising the positive charge — so the stability order is 3° > 2° > 1° > CH₃⁺.
Revision
Memorise these before attempting numericals — most exam questions hinge on one of them.
General formula (alkanes)
Alkenes / alkynes
IUPAC assembly
Carbocation stability
Aromatic rule
sp³/sp²/sp angles
Bond count
Exam tips
Where this topic appears in CBSE, JEE Main and NEET papers.
FAQ
Carbon is tetravalent and catenates — it forms four strong covalent bonds and chains with other carbons giving huge numbers of stable molecules in ring, chain and branched forms.
Find the longest chain, number it to give lowest locants, add main functional-group suffix and secondary suffix, then list substituents alphabetically — prefix + root + suffix.
The inductive effect is a permanent sigma-bond polarisation that falls off with distance; resonance is the delocalisation of π electrons over several atoms, giving an averaged, more stable structure than any single Lewis form.
Alkyl groups donate electron density by the +I effect and hyperconjugation, dispersing the positive charge. More groups around the charged carbon means more stabilisation: 3° > 2° > 1°.
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