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Class 12 Chemistry Notes

Organic Chemistry Class 12 Notes

Complete, exam-ready notes on organic chemistry for Class 12: IUPAC nomenclature, reaction mechanisms, haloalkanes and haloarenes, alcohols, aldehydes and ketones, carboxylic acids and amines — with named reactions written for CBSE boards, JEE and NEET revision.

Class12SubjectChemistryCoversCBSE · JEE · NEET

Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali

What is organic chemistry in one line?

Organic chemistry is the study of carbon compounds — their structure, properties, composition and reactions — where carbon's four-valency and catenation give rise to an enormous diversity of hydrocarbons and their functional-group derivatives.

IUPAC Nomenclature

The parent chain (longest continuous carbon chain) is numbered to give the lowest locant to the principal functional group. The suffix reflects the functional group; substituents are listed alphabetically with their locants.

  • Priority order for suffixes:
  • COOH>SO3H>COOR>COCl>CONH2>CN>CHO>CO>OH>NH2-COOH > -SO_3H > -COOR > -COCl > -CONH_2 > -CN > -CHO > -CO- > -OH > -NH_2
  • .
  • For multiple bonds use -ene, -yne; for functional groups use the appropriate suffix.
  • Numbering: principal functional group gets the lowest possible number.

Reaction Mechanisms and Intermediates

  • Carbocation:\text{Carbocation:}
  • sp², planar, electron-deficient — stability order
  • 3>2>1>CH3+3^\circ > 2^\circ > 1^\circ > \text{CH}_3^+
  • .
  • Carbanion:\text{Carbanion:}
  • electron-rich, pyramidal — stability order
  • CH3>1>2>3\text{CH}_3^- > 1^\circ > 2^\circ > 3^\circ
  • .
  • Free radical:\text{Free radical:}
  • stability
  • 3>2>13^\circ > 2^\circ > 1^\circ
  • .
  • SN1 favours tertiary substrates (carbocation intermediate); SN2 favours primary (concerted backside attack).

Haloalkanes and Haloarenes

Haloalkanes are formed by the replacement of H by halogen. Reactivity for SN2: R-I>R-Br>R-Cl>R-F\text{R-I} > \text{R-Br} > \text{R-Cl} > \text{R-F}. Haloarenes are much less reactive toward nucleophilic substitution than haloalkanes.

  • Finkelstein (NaI in acetone) converts R-Cl to R-I.
  • Swarts reaction (AgF/Hg₂F₂) converts R-Cl/R-Br to R-F.
  • Sandmeyer reaction: aryl diazonium + CuCl/CuBr gives halobenzenes.
  • Grignard reagent (RMgX) — a strong nucleophile and base.

Alcohols, Phenols and Ethers

Alcohols are distinguished by their boiling points (H-bonding) and acidity. Phenols are acidic because the phenoxide ion is resonance-stabilised; electron-withdrawing groups increase phenol acidity.

Lucas test

Alcohols react with ZnCl₂ + HCl; tertiary alcohols react instantly (cloudiness), secondary within minutes, primary are essentially unreactive at room temperature.

Williamson ether synthesis

Ethers are formed by the reaction of an alkoxide with an alkyl halide: R-O+R’XR-O-R’+X\text{R-O}^- + \text{R'X} \to \text{R-O-R'} + X^-. It is best suited for primary alkyl halides (avoids elimination).

Aldehydes and Ketones

  • Carbonyl carbon is attacked by nucleophiles; aldehydes are more reactive than ketones (less steric hindrance, more polar C=O).
  • Tollens' reagent (ammoniacal AgNO₃) — aldehydes give a silver mirror, ketones do not.
  • Fehling's test — aldehydes give a red Cu₂O precipitate; aromatic aldehydes do not.
  • Iodoform test — positive for CH₃-CO- group and secondary alcohols that oxidise to it.
  • Clemmensen (Zn-Hg/HCl) and Wolff-Kishner (NH₂NH₂/KOH) reduce a carbonyl to a methylene group.
R-CHONH2TollensR-COO+Ag\text{R-CHO} \xrightarrow[\text{NH}_2]{\text{Tollens}} \text{R-COO}^-+\text{Ag}
Tollens' test for aldehydes

Carboxylic Acids

Carboxylic acids are stronger acids than phenols and alcohols because the carboxylate anion is resonance stabilised. Electron-withdrawing groups (like -NO₂, -Cl) increase acidity; electron-donating groups decrease it.

  • Decarboxylation: heating a sodium salt with soda-lime gives an alkane.
  • Reduction with LiAlH₄ gives a primary alcohol.
  • Acid chloride formation via PCl₅, PCl₃ or SOCl₂.
  • Hell-Volhard-Zelinsky (HVZ) reaction: α-halogenation of acids with halogen + red phosphorus.

Amines

Amines are classified as primary, secondary or tertiary. Aliphatic amines are more basic than ammonia because alkyl groups donate electron density to nitrogen; aromatic amines (aniline) are much less basic.

  • Basicity in gas phase:
  • 3>2>1>NH33^\circ > 2^\circ > 1^\circ > \text{NH}_3
  • ; in aqueous phase solvation effects change the order.
  • Hinsberg test distinguishes 1°, 2° and 3° amines using benzenesulphonyl chloride.
  • Carbylamine reaction: a primary amine + CHCl₃ + KOH gives a foul-smelling isocyanide.
  • Diazotisation of aromatic primary amines with NaNO₂ + HCl gives diazonium salts.

Solved Examples

Example: Arrange in order of basicity: aniline, methylamine, dimethylamine, trimethylamine (aqueous).

Solution: In aqueous medium the order is 2>1>3>NH3>aniline2^\circ > 1^\circ > 3^\circ > \text{NH}_3 > \text{aniline}. Dimethylamine (2°) is most basic; aniline is least basic due to resonance delocalisation of the N lone pair into the ring.

Revision

Key formulas at a glance

Memorise these before attempting numericals — most exam questions hinge on one of them.

Carbocation stability

3>2>1>CH3+3^\circ > 2^\circ > 1^\circ > \text{CH}_3^+

SN2 reactivity

RI>RBr>RCl>RF\text{RI} > \text{RBr} > \text{RCl} > \text{RF}

Williamson synthesis

R-O+R’XR-O-R’\text{R-O}^- + \text{R'X} \to \text{R-O-R'}

Aldehyde > ketone reactivity

R-CHO more reactive than R-CO-R\text{R-CHO} \text{ more reactive than } \text{R-CO-R}

Basicity (amine)

2>1>3>NH3 (aq)2^\circ > 1^\circ > 3^\circ > \text{NH}_3 \text{ (aq)}

Exam tips

How this chapter is asked

Where this topic appears in CBSE, JEE Main and NEET papers.

  • Carbocation stability: 3° > 2° > 1°.
  • Tollens' test distinguishes aldehydes from ketones.
  • Iodoform test detects the CH₃-CO- group.
  • Phenols are acidic; electron-withdrawing groups increase acidity.
  • Hinsberg test separates 1°, 2°, 3° amines.

FAQ

Common questions

Why are aldehydes more reactive than ketones toward nucleophiles?

Aldehydes have less steric hindrance (one alkyl group vs two) and a more polar C=O bond, so nucleophiles attack them more easily.

What is the Hinsberg test?

Benzenesulphonyl chloride reacts with 1° amines (soluble sulphonamide), 2° amines (insoluble) and does not react with 3° amines, distinguishing the three classes.

Why are aromatic amines less basic?

The nitrogen lone pair is delocalised into the aromatic ring, making it less available to accept a proton, so aniline is a weaker base than aliphatic amines.

What does the Tollens' test detect?

It detects aldehydes: the aldehyde reduces ammoniacal AgNO₃ to a shiny silver mirror, while ketones do not react.

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