Class 11 Chemistry Notes
~9 min readThermodynamics Class 11 Chemistry Notes
Complete, exam-ready notes on chemical thermodynamics: systems and state functions, work and heat, the first law, enthalpy and calorimetry, Hess's law, bond enthalpies, entropy, Gibbs free energy and spontaneity — written for CBSE, JEE and NEET revision.
What is thermodynamics in one line?
Thermodynamics is the study of energy changes (heat and work) during physical and chemical processes, and the conditions (entropy and Gibbs free energy) that determine whether a process is spontaneous.
Systems, Work and Heat
- System types: open (matter + energy exchange), closed (energy only), isolated (neither).
- State functions (H, U, V, P, T) depend only on the current state, not the path; path functions (q, w) depend on how the change happens.
- Work done by a gas:
- .
- Sign convention: heat absorbed by the system q > 0, work done on the system w > 0.
First Law of Thermodynamics
First law
The change in internal energy of a system equals the heat added plus the work done on it (considering sign conventions). Equivalently, energy is conserved.
- For an ideal gas,
- .
- Adiabatic process (q = 0):
- .
- Isothermal process (ΔT = 0):
- , so
- .
Internal energy is a state function
Enthalpy and Calorimetry
Enthalpy
Enthalpy is the heat absorbed at constant pressure. For reactions at constant pressure, . Exothermic reactions have ; endothermic have .
- Enthalpy of formation: heat to form 1 mole of a compound from its elements.
- Standard enthalpy of reaction is measured at 298 K and 1 bar.
- Calorimetry measures heat using
- .
Hess's Law of Constant Heat Summation
Hess's law
The enthalpy change of a reaction is independent of the path taken — it depends only on the initial and final states. This lets us calculate ΔH for reactions that cannot be measured directly.
Reverse and scale reactions
Bond Enthalpy and Enthalpy of Combustion
Bond enthalpy
Bond enthalpy is the energy to break one mole of a bond. Estimate reaction ΔH by subtracting the bond enthalpies of bonds formed from those broken.
Sign care
Entropy and Spontaneity
Entropy
Entropy measures randomness (disorder). Systems tend toward increasing entropy. For an isolated system, — spontaneous processes increase entropy.
Gibbs free energy
Gibbs free energy determines spontaneity at constant T and P: spontaneous if , at equilibrium if , non-spontaneous if .
Predicting spontaneity
Solved Examples
Example: A reaction is exothermic with and at 300 K. Is it spontaneous?
Solution: . Since , the process is spontaneous.
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q5.1–Q5.22)
- 5.1) Choose the correct answer. A thermodynamic state function is a quantity: (i) used to determine heat changes. (ii) whose value is independent of path. (iii) used to determine pressure–volume work. (iv) whose value depends on temperature only.
- 5.2) For a process to occur under adiabatic conditions, the correct condition is: (i) ΔT = 0. (ii) Δp = 0. (iii) q = 0. (iv) w = 0.
- 5.3) The enthalpies of all elements in their standard states are: (i) unity. (ii) zero. (iii) less than zero. (iv) different for each element.
- 5.4) The standard combustion change in internal energy of methane is −X kJ mol⁻¹. Which relation gives its standard enthalpy change? (i) ΔH° = ΔU°. (ii) ΔH° > ΔU°. (iii) ΔH° < ΔU°. (iv) ΔH° = 0.
- 5.5) At 298 K, the enthalpies of combustion of methane, graphite and dihydrogen are −890.3 kJ mol⁻¹, −393.5 kJ mol⁻¹ and −285.8 kJ mol⁻¹, respectively. The enthalpy of formation of CH₄(g) is: (i) −74.8 kJ mol⁻¹. (ii) −52.27 kJ mol⁻¹. (iii) +74.8 kJ mol⁻¹. (iv) +52.26 kJ mol⁻¹.
- 5.6) A reaction A + B → C + D + q is found to have a positive entropy change. The reaction will be: (i) possible at high temperature. (ii) possible only at low temperature. (iii) not possible at any temperature. (iv) possible at any temperature.
- 5.7) In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy?
- 5.8) The reaction of cyanamide, NH₂CN(s), with dioxygen was carried out in a bomb calorimeter. Its ΔU was −742.7 kJ mol⁻¹ at 298 K. Calculate the enthalpy change for the reaction:
- 5.9) Calculate the heat needed to raise the temperature of 60.0 g of aluminium from 35 °C to 55 °C. The molar heat capacity of Al is 24 J mol⁻¹ K⁻¹.
- 5.10) Calculate the enthalpy change when 1.0 mol of water at 10.0 °C freezes to ice at −10.0 °C. The enthalpy of fusion at 0 °C is 6.03 kJ mol⁻¹.
- 5.11) The enthalpy of combustion of carbon to CO₂ is −393.5 kJ mol⁻¹. Calculate the heat released when 35.2 g of CO₂ is formed from carbon and dioxygen.
- 5.12) The standard enthalpies of formation of CO(g), CO₂(g), N₂O(g) and N₂O₄(g) are −110, −393, +81 and +9.7 kJ mol⁻¹, respectively. Find ΔᵣH° for N₂O₄(g) + 3CO(g) → N₂O(g) + 3CO₂(g).
- 5.13) For N₂(g) + 3H₂(g) → 2NH₃(g), ΔᵣH° = −92.4 kJ mol⁻¹. What is the standard enthalpy of formation of NH₃(g)?
- 5.14) Calculate the standard enthalpy of formation of CH₃OH(l) from these data:
- 5.15) Calculate the enthalpy change for CCl₄(g) → C(g) + 4Cl(g), and then calculate the C–Cl bond enthalpy in gaseous CCl₄. Given ΔᵥₐₚH°(CCl₄) = 30.5 kJ mol⁻¹, ΔfH°(CCl₄(g)) = −135.5 kJ mol⁻¹, ΔₐH°(C) = 715.0 kJ mol⁻¹ and ΔₐH°(Cl₂) = 242 kJ mol⁻¹.
- 5.16) For an isolated system, ΔU = 0. What will be ΔS?
- 5.17) For 2A + B → C at 298 K, ΔH = 400 kJ mol⁻¹ and ΔS = 0.2 kJ K⁻¹ mol⁻¹. At what temperature does the reaction become spontaneous if ΔH and ΔS remain constant?
- 5.18) For 2Cl(g) → Cl₂(g), what are the signs of ΔH and ΔS?
- 5.19) For 2A(g) + B(g) → 2D(g) at 298 K, ΔU° = −10.5 kJ and ΔS° = −44.1 J K⁻¹. Calculate ΔG° and predict whether the reaction may occur spontaneously.
- 5.20) The equilibrium constant for a reaction is 10. Find ΔG° at 300 K when R = 8.314 J K⁻¹ mol⁻¹.
- 5.21) Comment on the thermodynamic stability of NO(g) from these data:
- 5.22) Calculate the entropy change of the surroundings when 1.00 mol of H₂O(l) is formed under standard conditions, given ΔfH° = −286 kJ mol⁻¹ at 298 K.
Answers at a glance
- 1Q5.1 → A state function has a path-independent value, so the correct option is (ii).
- 2Q5.2 → An adiabatic process satisfies q = 0, so the correct option is (iii).
- 3Q5.3 → The standard enthalpy of every element in its standard state is 0 kJ mol⁻¹, so option (ii) is correct.
- 4Q5.4 → ΔH° = ΔU° − RT, so ΔH° < ΔU° and option (iii) is correct.
- 5Q5.5 → The enthalpy of formation of CH₄(g) is −74.8 kJ mol⁻¹, so option (i) is correct.
- 6Q5.6 → The reaction is possible at any temperature, so the corrected fourth option (iv) is correct.
- 7Q5.7 → The change in internal energy is ΔU = +307 J.
- 8Q5.8 → The standard reaction enthalpy at 298 K is ΔH° = −741.5 kJ mol⁻¹.
- 9Q5.9 → The required heat is 1.07 kJ for the 60.0 g sample.
- 10Q5.10 → The enthalpy change from liquid water at 10 °C to ice at −10 °C is −7.151 kJ mol⁻¹.
- 11Q5.11 → Forming 35.2 g of CO₂ releases 314.8 kJ of heat, corresponding to ΔH = −314.8 kJ for the sample.
- 12Q5.12 → The standard reaction enthalpy is ΔᵣH° = −777.7 kJ mol⁻¹.
- 13Q5.13 → The standard enthalpy of formation of NH₃(g) is −46.2 kJ mol⁻¹.
- 14Q5.14 → The standard enthalpy of formation of CH₃OH(l) is −239 kJ mol⁻¹.
- 15Q5.15 → The reaction enthalpy is +1304 kJ mol⁻¹, and the C–Cl bond enthalpy is 326 kJ mol⁻¹.
- 16Q5.16 → For the expected spontaneous change, ΔS is positive; ΔS = 0 only for an ideal reversible change.
- 17Q5.17 → The reaction is spontaneous for T > 2000 K; at 2000 K it is at equilibrium.
- 18Q5.18 → Both enthalpy and entropy decrease, so ΔH < 0 and ΔS < 0.
- 19Q5.19 → ΔG° ≈ +0.16 kJ for the reaction as written, so it is not spontaneous under the stated standard conditions.
- 20Q5.20 → The standard Gibbs energy change is ΔG° = −5.744 kJ mol⁻¹.
- 21Q5.21 → NO(g) is unstable relative to its elements, while its conversion to the lower-enthalpy NO₂(g) is energetically favoured.
- 22Q5.22 → The entropy change of the surroundings is ΔS(surr) = +959.73 J mol⁻¹ K⁻¹.
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1Define enthalpy (H). (Ans: H = U + PV — the heat content of a system at constant pressure)
- 2State the first law of thermodynamics. (Ans: energy can neither be created nor destroyed; ΔU = q + w)
- 3What is a spontaneous process? (Ans: a process that occurs on its own without any external driving force at a given temperature and pressure)
- 4Define entropy. (Ans: a measure of disorder/randomness of the system; ΔS = q_rev/T)
2 Mark Questions
- 1Differentiate between exothermic and endothermic reactions. (Ans: heat released vs absorbed; ΔH < 0 vs ΔH > 0)
- 2State Hess's law of constant heat summation. (Ans: the total enthalpy change of a reaction is the same whether it occurs in one step or in several steps)
- 3What is the relation between ΔH and ΔU for a reaction at constant pressure? (Ans: ΔH = ΔU + Δn_g RT)
3 Mark Questions
- 1Using the first law, derive ΔH = ΔU + PΔV and explain the conditions under which ΔH = ΔU. (Ans: at constant pressure; equal when no gaseous volume change — Δn_g = 0)
- 2Calculate the standard enthalpy of the reaction N₂(g) + 3H₂(g) → 2NH₃(g) if bond enthalpies are N≡N = 946, H–H = 436, N–H = 391 kJ mol⁻¹. (Ans: ΔH = 2(946) + 3(436) − 6(391) = −92 kJ mol⁻¹)
- 3State the second law of thermodynamics and explain its relationship to entropy and spontaneity. (Ans: total entropy of the universe increases in a spontaneous change)
5 Mark Questions
- 1Define Gibbs free energy. Derive ΔG = ΔH − TΔS and explain the criteria of spontaneity (ΔG < 0 spontaneous, ΔG = 0 equilibrium, ΔG > 0 non-spontaneous) with examples of the four sign combinations of ΔH and ΔS.
- 2Explain Hess's law with a full worked example (e.g. ΔH°f of CO from the combustion of C and CO), and define the standard enthalpies of formation, combustion and neutralisation with one numerical application of each.
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Practice path: complete Assignment 1 first (topic-by-topic), then Assignment 2 (mixed difficulty with full solutions), then attempt the timed tests.
Covers all six topics: systems, work and heat; first law of thermodynamics; enthalpy and calorimetry; Hess's law of constant heat summation; bond enthalpy and enthalpy of combustion; and entropy and spontaneity. Arranged topic by topic.
Higher-difficulty set with multi-step numerical problems (ΔU and ΔH calculations, ΔH = ΔU + Δn_gRT, Hess's law, bond enthalpy, ΔG and spontaneity) and full worked answers. Includes an answer key.
Full board-pattern test: Section A (MCQ/VSA 1M × 10), Section B (2M × 4), Section C (3M × 4), Section D (5M × 2) = 40 marks. Time: 90 minutes. Includes answer key.
Second full paper with different questions, same 40-mark / 90-minute blueprint. Includes answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
First law
Enthalpy
Hess's law
Bond enthalpy
Gibbs free energy
Spontaneity
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- ΔU = q + w is the first law (sign conventions matter).
- q_p = ΔH at constant pressure.
- Hess's law: ΔH is path independent.
- ΔG < 0 → spontaneous; ΔG = 0 → equilibrium.
- Breaking bonds is endothermic; forming bonds is exothermic.
FAQ
Frequently asked questions
What is Gibbs free energy?
Gibbs free energy G = H − TS. The change ΔG = ΔH − TΔS decides spontaneity at constant temperature and pressure: negative means spontaneous, zero means equilibrium.
What is the first law of thermodynamics?
Energy is conserved: the change in internal energy ΔU equals heat added (q) plus work done on the system (w), i.e. ΔU = q + w.
What is Hess's law?
The enthalpy change of a reaction depends only on the initial and final states, not the path, so it is the sum of the ΔH of its steps. It is used to find ΔH for unmeasurable reactions.
What is entropy?
Entropy is a measure of disorder or randomness. Spontaneous processes in an isolated system increase entropy, with ΔS ≥ 0.
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