Class 12 Maths Notes
~7 min readVector Algebra Class 12 Notes
Complete, exam-ready notes on vector algebra: components and position vectors, the dot and cross products, projection of vectors and their geometric meaning — written for CBSE boards and JEE revision.
What is this chapter about in one line?
Vector algebra describes quantities with both magnitude and direction, and the dot and cross products let you measure angles, projections and areas.
Vectors and Components
Position vector
A vector has magnitude and direction. The position vector of point is with magnitude .
Dot (Scalar) Product
Dot product
The dot product is a scalar measuring how much two vectors point together: . Two non-zero vectors are perpendicular exactly when their dot product is zero.
Cross (Vector) Product
Cross product
The cross product of two non-parallel vectors is a vector perpendicular to both, with magnitude equal to the parallelogram area. For parallel vectors it is the zero vector.
Collinearity and Coplanarity
- Points A, B, C are collinear if
- (the displacement vectors are parallel).
- Vectors are coplanar if their scalar triple product is zero:
- .
- Area of a parallelogram with sides
- is
- ; a triangle takes half of it.
Solved Examples
Example: Find the angle between and .
Solution: , , , so and .
Example: Find the area of the triangle with vertices .
Solution: Take and . Then with length , and the triangle area is half of that: .
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q1–Q54)
- 1) Represent graphically a displacement of 40 km, 30° west of north.
- 2) Classify the following measures as scalars and vectors: (i) 10 kg (ii) 2 metres north-west (iii) 40° (iv) 40 watt (v) 10⁻¹⁹ coulomb (vi) 20 m/s².
- 3) Classify the following as scalar and vector quantities: (i) time period (ii) distance (iii) force (iv) velocity (v) work done.
- 4) In the square figure (Fig 10.6) with centre O, the directed segments a, b, c and d are marked. Identify the vectors which are (i) coinitial, (ii) equal, (iii) collinear but not equal.
- 5) Answer the following as true or false: (i) a and −a are collinear. (ii) Two collinear vectors are always equal in magnitude. (iii) Two vectors having the same magnitude are collinear. (iv) Two collinear vectors having the same magnitude are equal.
- 6) Compute the magnitude of the following vectors: a = î + ĵ + k̂, b = 2î − 7ĵ − 3k̂ and c = (1/√3)î + (1/√3)ĵ − (1/√3)k̂.
- 7) Write two different vectors having the same magnitude.
- 8) Write two different vectors having the same direction.
- 9) Find the values of x and y so that the vectors 2î + 3ĵ and xî + yĵ are equal.
- 10) Find the scalar and vector components of the vector with initial point (2, 1) and terminal point (−5, 7).
- 11) Find the sum of the vectors a = î − 2ĵ + k̂, b = −2î + 4ĵ + 5k̂ and c = î − 6ĵ − 7k̂.
- 12) Find the unit vector in the direction of the vector a = î + ĵ + 2k̂.
- 13) Find the unit vector in the direction of the vector PQ, where P and Q are the points (1, 2, 3) and (4, 5, 6) respectively.
- 14) For given vectors a = 2î − ĵ + 2k̂ and b = −î + ĵ − k̂, find the unit vector in the direction of the vector a + b.
- 15) Find a vector in the direction of the vector 5î − ĵ + 2k̂ which has magnitude 8 units.
- 16) Show that the vectors 2î − 3ĵ + 4k̂ and −4î + 6ĵ − 8k̂ are collinear.
- 17) Find the direction cosines of the vector î + 2ĵ + 3k̂.
- 18) Find the direction cosines of the vector joining the points A (1, 2, −3) and B (−1, −2, 1), directed from A to B.
- 19) Show that the vector î + ĵ + k̂ is equally inclined to the axes OX, OY and OZ.
- 20) Find the position vector of a point R which divides the line joining the points P and Q, whose position vectors are î + 2ĵ − k̂ and −î + ĵ + k̂ respectively, in the ratio 2 : 1, (i) internally, (ii) externally.
- 21) Find the position vector of the mid point of the vector joining the points P (2, 3, 4) and Q (4, 1, −2).
- 22) Show that the points A, B and C with position vectors a = 3î − 4ĵ − 4k̂, b = 2î − ĵ + k̂ and c = î − 3ĵ − 5k̂ respectively form the vertices of a right angled triangle.
- 23) In triangle ABC, which of the following is not true? (A) AB + BC + CA = 0 (B) AB + BC − AC = 0 (C) AB + BC − CA = 0 (D) AB − CB + CA = 0.
- 24) If a and b are two collinear vectors, then which of the following are incorrect? (A) b = λa for some scalar λ (B) a = ± b (C) the respective components of a and b are proportional (D) both vectors a and b have the same direction, but different magnitudes.
- 25) Find the angle between two vectors a and b with magnitudes √3 and 2, respectively, having a·b = √6.
- 26) Find the angle between the vectors î − 2ĵ + 3k̂ and 3î − 2ĵ + k̂.
- 27) Find the projection of the vector î − ĵ on the vector î + ĵ.
- 28) Find the projection of the vector î + 3ĵ + 7k̂ on the vector 7î − ĵ + 8k̂.
- 29) Show that each of the given three vectors is a unit vector — (2î + 3ĵ + 6k̂)/7, (3î − 6ĵ + 2k̂)/7, (6î + 2ĵ − 3k̂)/7. Also show that they are mutually perpendicular to each other.
- 30) Find |a| and |b|, if (a + b)·(a − b) = 8 and |a| = 8|b|.
- 31) Evaluate the product (3a − 5b)·(2a + 7b).
- 32) Find the magnitude of two vectors a and b, having the same magnitude and such that the angle between them is 60° and their scalar product is 1/2.
- 33) Find |x|, if for a unit vector a, (x − a)·(x + a) = 12.
- 34) If a = 2î + 2ĵ + 3k̂, b = −î + 2ĵ + k̂ and c = 3î + ĵ are such that a + λb is perpendicular to c, then find the value of λ.
- 35) Show that |a| b + |b| a is perpendicular to |a| b − |b| a, for any two non-zero vectors a and b.
- 36) If a·a = 0 and a·b = 0, then what can be concluded about the vector b?
- 37) If a, b, c are unit vectors such that a + b + c = 0, find the value of a·b + b·c + c·a.
- 38) If either vector a = 0 or b = 0, then a·b = 0. But the converse need not be true. Justify your answer with an example.
- 39) If the vertices A, B, C of a triangle ABC are (1, 2, 3), (−1, 0, 0), (0, 1, 2), respectively, then find ∠ABC.
- 40) Show that the points A (1, 2, 7), B (2, 6, 3) and C (3, 10, −1) are collinear.
- 41) Show that the vectors 2î − ĵ + k̂, î − 3ĵ − 5k̂ and 3î − 4ĵ − 4k̂ form the vertices of a right angled triangle.
- 42) If a is a non-zero vector of magnitude 'a' and λ is a non-zero scalar, then λa is a unit vector if: (A) λ = 1 (B) λ = −1 (C) a = |λ| (D) a = 1/|λ|.
- 43) Find |a × b|, if a = î − 7ĵ + 7k̂ and b = 3î − 2ĵ + 2k̂.
- 44) Find a unit vector perpendicular to each of the vectors a + b and a − b, where a = 3î + 2ĵ + 2k̂ and b = î + 2ĵ − 2k̂.
- 45) If a unit vector a makes angles π/3 with î, π/4 with ĵ and an acute angle θ with k̂, then find θ and hence the components of a.
- 46) Show that (a − b) × (a + b) = 2(a × b).
- 47) Find λ and μ if (2î + 6ĵ + 27k̂) × (î + λĵ + μk̂) = 0.
- 48) Given that a·b = 0 and a × b = 0. What can you conclude about the vectors a and b?
- 49) Let the vectors a, b, c be given as a₁î + a₂ĵ + a₃k̂, b₁î + b₂ĵ + b₃k̂ and c₁î + c₂ĵ + c₃k̂ respectively. Showing the component-wise expansion, prove that a × (b + c) = a × b + a × c.
- 50) If either a = 0 or b = 0, then a × b = 0. Is the converse true? Justify your answer with an example.
- 51) Find the area of the triangle with vertices A (1, 1, 2), B (2, 3, 5) and C (1, 5, 5).
- 52) Find the area of the parallelogram whose adjacent sides are determined by the vectors a = î − ĵ + 3k̂ and b = 2î − 7ĵ + k̂.
- 53) Let the vectors a and b be such that |a| = 3 and |b| = √2/3. Then a × b is a unit vector if the angle between a and b is (A) π/6 (B) π/4 (C) π/3 (D) π/2.
- 54) Area of a rectangle having vertices A, B, C and D with position vectors −î + ½ĵ + 4k̂, î + ½ĵ + 4k̂, î − ½ĵ + 4k̂ and −î − ½ĵ + 4k̂ respectively is (A) ½ (B) 1 (C) 2 (D) 4.
Answers at a glance
- 1Q1 → An arrow of 40 km magnitude pointing 30° west of north (drawn 4 cm long at scale 10 km = 1 cm).
- 2Q2 → (i) scalar (ii) vector (iii) scalar (iv) scalar (v) scalar (vi) vector.
- 3Q3 → (i) scalar (ii) scalar (iii) vector (iv) vector (v) scalar.
- 4Q4 → (i) a and d; (ii) b and d; (iii) a and c.
- 5Q5 → (i) True (ii) False (iii) False (iv) False.
- 6Q6 → |a| = √3, |b| = √62 and |c| = 1.
- 7Q7 → a = î + ĵ + k̂ and b = î + ĵ − k̂ (both of magnitude √3).
- 8Q8 → a = î + 2ĵ + 3k̂ and b = 2î + 4ĵ + 6k̂ (b = 2a).
- 9Q9 → x = 2, y = 3.
- 10Q10 → Scalar components −7 and 6; vector components −7î and 6ĵ.
- 11Q11 → a + b + c = −4ĵ − k̂.
- 12Q12 → answer not in source — verify against the textbook
- 13Q13 → answer not in source — verify against the textbook
- 14Q14 → answer not in source — verify against the textbook
- 15Q15 → answer not in source — verify against the textbook
- 16Q16 → Collinear, since −4î + 6ĵ − 8k̂ = −2(2î − 3ĵ + 4k̂).
- 17Q17 → l = 1/√14, m = 2/√14, n = 3/√14.
- 18Q18 → Direction cosines are −1/3, −2/3, 2/3.
- 19Q19 → All three direction cosines are 1/√3, so the vector is equally inclined to OX, OY, OZ.
- 20Q20 → (i) (−î + 4ĵ + k̂)/3; (ii) −3î + 3k̂.
- 21Q21 → 3î + 2ĵ + k̂ (point (3, 2, 1)).
- 22Q22 → The triangle is right angled at A.
- 23Q23 → Option (C).
- 24Q24 → Incorrect: (B) and (D).
- 25Q25 → answer not in source — verify against the textbook
- 26Q26 → θ = cos⁻¹(5/7).
- 27Q27 → 0.
- 28Q28 → answer not in source — verify against the textbook
- 29Q29 → Each is a unit vector and every pair has zero dot product — mutually perpendicular.
- 30Q30 → answer not in source — verify against the textbook
- 31Q31 → answer not in source — verify against the textbook
- 32Q32 → |a| = |b| = 1.
- 33Q33 → |x| = √13.
- 34Q34 → λ = 8.
- 35Q35 → The dot product is zero, so the vectors are perpendicular.
- 36Q36 → a is the zero vector; b is arbitrary.
- 37Q37 → answer not in source — verify against the textbook
- 38Q38 → a = î and b = ĵ give a·b = 0 with a, b both non-zero — the converse fails.
- 39Q39 → ∠ABC = cos⁻¹(10/√102).
- 40Q40 → AB = BC, so A, B, C are collinear.
- 41Q41 → The triangle is right angled at C.
- 42Q42 → Option (D).
- 43Q43 → 19√2.
- 44Q44 → answer not in source — verify against the textbook
- 45Q45 → answer not in source — verify against the textbook
- 46Q46 → (a − b) × (a + b) = 0 + a×b + a×b − 0 = 2(a × b).
- 47Q47 → answer not in source — verify against the textbook
- 48Q48 → Either a = 0 or b = 0.
- 49Q49 → a × (b + c) = a × b + a × c (right-distributive law verified).
- 50Q50 → Converse is false: parallel non-zero vectors, e.g. î and 2î, have zero cross product.
- 51Q51 → answer not in source — verify against the textbook
- 52Q52 → Area = 15√2.
- 53Q53 → Option (B).
- 54Q54 → Option (C) — area 2.
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1Write a unit vector in the direction of a = 3i + 4j. (Ans: (3i + 4j)/5)
- 2When is the dot product of two non-zero vectors zero? (Ans: when they are perpendicular)
- 3Give the magnitude of i × j. (Ans: 1)
- 4State the condition for two vectors to be collinear. (Ans: one is a scalar multiple of the other)
2 Mark Questions
- 1If a = 2i − j + k and b = i + 3j − 2k, find a·b. (Ans: 2 − 3 − 2 = −3)
- 2Find the angle between a = i + j and b = i − j. (Ans: 90°)
- 3Find a unit vector perpendicular to a = 2i + j and b = i + 2j. (Ans: ±k/√... (a × b)/|a × b| = ±k)
3 Mark Questions
- 1Find the projection of a = 2i − j + k on b = i + 2j + 2k. (Ans: (a·b)/|b| = (2 − 2 + 2)/3 = 2/3)
- 2Show that the vectors a = 3i − 2j + k, b = i − 3j + 5k, c = 2i + j − 4k form a right-angled triangle by computing a + b = ? Check endpoints and dot products. (Ans: a + b = 4i − 5j + 6k = c + ... identity verified)
- 3If a, b are unit vectors inclined at 60°, find |a + b|. (Ans: √(1 + 1 + 2(1/2)) = √3)
4 Mark Questions
- 1If a = 2i + 3j + k and b = 3i − j + 2k, find (a + b)·(a − b), |a + b|, |a − b| and the angle between a and b. Summarise which results use dot and which use algebra.
- 2Prove the vector identity (a + b) × (a − b) = 2(b × a), then use it with a = 2i + j and b = i + 2j to find the area of the parallelogram they span. (Ans: area = |a × b| = 3 sq units)
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Practice path: complete Assignment 1 first (topic-by-topic), then Assignment 2 (mixed difficulty with full solutions), then attempt the timed tests.
Covers all four topics: vectors and components; dot (scalar) product; cross (vector) product; and collinearity and coplanarity.
Higher-difficulty set with multi-step problems (unit vectors, direction ratios, angles and projections, areas of triangles, perpendicular vectors, scalar triple product) with full worked answers. Includes an answer key.
Full board-pattern test: Section A (MCQ/VSA 1M × 10), Section B (2M × 4), Section C (3M × 4), Section D (5M × 2) = 40 marks. Time: 90 minutes. Includes answer key.
Second full paper with different questions, same 40-mark / 90-minute blueprint. Includes answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Magnitude
Dot product
Cross product magnitude
Projection
Parallelogram area
Coplanarity
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- Dot product zero ⟺ perpendicular vectors; cross product zero ⟺ parallel vectors.
- The cross product magnitude is the parallelogram area; the triangle area is half.
- A unit vector in any direction is the vector divided by its magnitude.
- Scalar triple product zero ⟺ the three vectors are coplanar.
- Position vectors from the origin make displacement vectors by subtraction.
FAQ
Frequently asked questions
What is the difference between dot and cross product?
The dot product returns a scalar measuring how aligned two vectors are, while the cross product returns a new vector perpendicular to both, whose magnitude is the parallelogram area.
When is the dot product zero?
When the vectors are perpendicular (θ = 90°), since cos 90° = 0. Also if either vector is the zero vector.
How do you find a unit vector?
Divide the vector by its magnitude: â = a/|a|. The unit vector has the same direction but magnitude 1.
How is the area of a triangle related to vectors?
The area of a triangle with adjacent sides a and b is half the magnitude of their cross product: (1/2)|a × b|.
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