Class 11 Chemistry Notes
Complete, exam-ready notes on the p-block elements: where they sit in the periodic table, the general trends down the groups, the inert pair effect, the boron family (Group 13) with diborane and borax, and the carbon family (Group 14) with allotropes, silicates and silicones — written for CBSE, JEE and NEET revision.
Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali
The p-block elements fill the p subshell (ns²np¹ to ns²np⁶) and span Groups 13 to 18, containing metals, metalloids and non-metals with the whole range of oxidation states.
The last six groups (13 to 18) hold the p-block: valence shell configuration ns²np¹ to ns²np⁶. Only helium of Group 18 is actually an s-block element; the rest have a filled s plus partially filled p subshell.
Down each group the heavier elements increasingly prefer the lower oxidation state (group number − 2) because the ns² pair is reluctant to participate in bonding. Tl⁺, Sn²⁺, Pb²⁺ and Bi³⁺ are all stable, halide chemistry included — the driving force behind the inert pair effect.
Diborane is the simplest boron hydride. It has a 'banana bond' structure where two hydrogen bridges hold the boron atoms together — each bridge is a three-centre two-electron (3c-2e) bond. It is spontaneously flammable and hydrolyses in water to boric acid with hydrogen gas.
Silicon forms SiO₄⁴⁻ tetrahedra that link in chains, sheets or 3-D networks — the silicate minerals (nepheline, asbestos, mica, feldspar, quartz).
Silicones are polymers with Si–O backbones and organic groups on silicon. They are stable, water-resistant, and used in sealants, lubricants and waterproofing because the Si–O bond is very strong.
Aluminosilicate frameworks with pores that trap molecules by size — natural or synthetic sieves used in water softening, catalysis and ion exchange.
Example: Why is PbCl₂ stable but PbCl₄ unstable?
Solution: The inert pair effect makes the ns² electrons of lead reluctant to bond, so the +2 state is preferred. Pb⁴⁺ is strongly oxidising and PbCl₄ tends to lose chlorine, whereas PbCl₂ is covalent and stable.
Example: Which factor decides metallic character within the p-block?
Solution: Metallic character increases down a group because the ionisation enthalpy falls and the atomic size increases, so electrons are lost more easily. Metals give way to metalloids and then non-metals as you move right across the p-block.
Revision
Memorise these before attempting numericals — most exam questions hinge on one of them.
p-block configuration
Highest oxidation state
Inert pair oxidation states
Silicate unit
Hydrolysis of diborane
Silicone backbone
Boric acid as Lewis acid
Exam tips
Where this topic appears in CBSE, JEE Main and NEET papers.
FAQ
Elements of Groups 13–18 whose valence electrons fill the p subshell, with configurations from ns²np¹ to ns²np⁶. They include metals, metalloids and non-metals with oxidation states from +group number down to −3.
Down the group, the ns² pair of electrons becomes reluctant to take part in bonding, so heavier elements prefer an oxidation state two less than the group number — for example Tl⁺, Pb²⁺, Sn²⁺ and Bi³⁺.
Boron has a very small size, high ionisation enthalpy and lacks d-orbitals. It forms covalent, electron-deficient compounds like diborane (with 3-centre-2-electron bonds) and shows a diagonal relationship with silicon.
Diamond is a 3-D covalent network of carbons — the hardest natural substance. Graphite has flat layers of hexagons with weak van der Waals forces between layers, so it is soft, slippery and conducts electricity.
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