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Class 12 Biology Notes

Principles of Inheritance and Variation Class 12 Notes

Complete, exam-ready notes on principles of inheritance and variation — Mendel's laws, monohybrid and dihybrid crosses, extensions of Mendelism, linkage, sex determination, sex-linked disorders, pedigree analysis, chromosomal and Mendelian disorders. Essential for CBSE Board and NEET revision.

Class12SubjectBiologyCoversCBSE · NEET

Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali

What are Mendel's two key laws?

Law of Segregation: alleles separate during gamete formation. Law of Independent Assortment: genes for different traits segregate independently during gamete formation (valid for unlinked genes on different chromosomes).

Mendel's Experiments and Laws of Inheritance

Gregor Johann Mendel, the father of genetics, conducted hybridization experiments on garden pea (Pisum sativum) for seven years (1856–1863) with 29,000 plants. He chose pea plants for their short life cycle, easily distinguishable contrasting characters, natural self-pollination (and ability to cross-pollinate manually), and pure-breeding lines.

Monohybrid Cross

Law of Segregation

When two contrasting alleles are present (heterozygous), they segregate during gamete formation so that each gamete carries only one allele. In a monohybrid cross (Tt × Tt), the F₂ generation shows a phenotypic ratio of 3:1 (tall: dwarf) and genotypic ratio of 1:2:1 (TT:Tt:tt). The 3:1 ratio appears because alleles segregate randomly during gamete formation and recombine during fertilization.

F2 phenotypic ratio=3:1(Tall : Dwarf)\text{F}_2 \text{ phenotypic ratio} = 3 : 1 \quad (\text{Tall : Dwarf})
Monohybrid ratio

Dihybrid Cross

Law of Independent Assortment

When two pairs of contrasting traits are considered simultaneously (YyRr × YyRr), alleles of different genes segregate independently of each other during gamete formation. The F₂ generation shows a phenotypic ratio of 9:3:3:1 (round yellow : round green : wrinkled yellow : wrinkled green). This holds only for genes on different chromosomes or far apart on the same chromosome.

F2 phenotypic ratio=9:3:3:1\text{F}_2 \text{ phenotypic ratio} = 9 : 3 : 3 : 1
Dihybrid ratio
  • Test cross: crossing an F₁ individual with the homozygous recessive parent to determine its genotype. If all offspring show the dominant trait, the parent was homozygous; if 1:1 ratio appears, the parent was heterozygous.
  • Back cross: crossing an F₁ individual with any of the two homozygous parental types.

Extensions of Mendelism

Incomplete Dominance

Incomplete dominance

The heterozygous phenotype is an intermediate blend of the two homozygous phenotypes. In snapdragon (Antirrhinum), a cross between red (RR) and white (rr) flowers produces pink (Rr) F₁ flowers. The F₂ ratio is 1:2:1 (red : pink : white), which holds for both genotype and phenotype — no complete dominance.

Co-dominance

Co-dominance

Both alleles are equally and simultaneously expressed in the heterozygote. In ABO blood groups, the Iᵃ and Iᵇ alleles are co-dominant — a person with genotype IᵃIᵇ has blood type AB, expressing both A and B antigens on the red blood cells. The O allele (i) is recessive.

  • Multiple alleles: More than two alleles exist for a gene in a population (e.g. ABO system has Iᵃ, Iᵇ and i). An individual still carries only two.
  • Pleiotropy: A single gene affects multiple unrelated phenotypic characters (e.g. pea gene for seed shape also affects flower colour and pod shape).

Polygenic Inheritance

Polygenic inheritance

Traits controlled by two or more genes, each contributing additively. Skin colour in humans is controlled by at least 3 genes, producing a continuous spectrum of phenotypes. Quantitative traits like height, weight and eye colour show polygenic inheritance with environmental influence.

Linkage, Recombination and Sex Determination

T.H. Morgan's experiments with Drosophila melanogaster demonstrated that genes on the same chromosome tend to be inherited together — this is linkage. Linked genes do not follow independent assortment. Recombination is the formation of new combinations of linked genes due to crossing over during meiosis, producing recombinant offspring that differ from parental types.

Linkage map

Morgan mapped gene positions on chromosomes using recombination frequencies. The farther apart two genes are, the more likely crossing over will occur between them, and the higher the recombination frequency. One map unit (1 cM) equals 1% recombination frequency. Morgan's Drosophila work established the chromosome theory of inheritance.

Sex Determination

  • XX/XY system: Females are XX (homogametic), males are XY (heterogametic). The Y chromosome carries the SRY gene that triggers male development.
  • ZW/ZZ system (birds): Females are ZW (heterogametic), males are ZZ (homogametic).
  • Criss-cross (X-linked) inheritance: A trait on the X chromosome is passed from a carrier mother to affected sons, and from an affected father to carrier daughters.

Sex-Linked Disorders

Colour blindness

An X-linked recessive disorder where the eye cannot distinguish red and green. The gene for the red/green photopigment is on the X chromosome. Males (XY) are more commonly affected because they need only one copy of the defective allele. A carrier mother (XᶜX) has a 50% chance of producing an affected son. The disease cannot be transmitted from father to son (since the father gives Y, not X).

Haemophilia

An X-linked recessive blood clotting disorder caused by deficiency of clotting factor VIII (haemophilia A) or factor IX (haemophilia B). Like colour blindness, it is more common in males. A carrier mother (XᴴXʰ) has a 50% chance of producing an affected son. Queen Victoria was a carrier, and the disease spread through European royal families by criss-cross inheritance.

Pedigree Analysis

Pedigree analysis is the study of inheritance of traits through generations of a family using standard symbols. Squares represent males, circles represent females, shaded shapes are affected individuals, and half-shaded are carriers. It helps determine whether a trait is dominant or recessive, autosomal or sex-linked, and predicts the probability of a trait appearing in offspring.

  • Autosomal dominant: affected individuals appear in every generation; affected individuals have at least one affected parent.
  • Autosomal recessive: affected individuals may skip generations; affected offspring can be born to unaffected (carrier) parents.
  • X-linked recessive: more males affected; no male-to-male transmission; affected daughters have an affected father.

Chromosomal and Mendelian Disorders

Chromosomal Disorders

  • Down syndrome (Trisomy 21): 2n = 47, caused by the presence of an extra copy of chromosome 21. Symptoms: mental retardation, characteristic facial features (flat face, protruding tongue), short stature, single palmar crease.
  • Turner syndrome: XO (2n = 45), absence of one X chromosome in females. Symptoms: sterile female, short stature, webbed neck, shield-shaped chest.
  • Klinefelter syndrome: XXY (2n = 47), an extra X chromosome in males. Symptoms: sterile male, gynaecomastia (breast enlargement), long limbs.

Mendelian Disorders

  • Sickle-cell anaemia: autosomal recessive; point mutation in β-globin gene (GAG → GUG); HbS polymerizes in low oxygen.
  • Phenylketonuria (PKU): autosomal recessive; deficiency of phenylalanine hydroxylase; untreated causes intellectual disability.
  • Thalassemia: autosomal recessive; reduced synthesis of α or β globin chains; results in anaemia of varying severity.
  • Cystic fibrosis: autosomal recessive; mutation in CFTR gene; thick mucus in lungs, pancreas.

Solved Examples

Example: In a pedigree, you observe that a trait appears in every generation and every affected individual has at least one affected parent. Affected males and females appear with equal frequency. What is the mode of inheritance?

Solution: The trait appearing in every generation and requiring only one affected parent indicates an autosomal dominant mode of inheritance. Equal frequency in males and females rules out X-linked inheritance. There are no skipped generations, which is characteristic of dominant traits. If the trait were recessive, affected individuals could have unaffected parents (carriers).

Example: A colour-blind man marries a woman with normal vision whose father was colour-blind. What proportion of their children will be affected? Show your work using a Punnett square approach.

Solution: The man is XᶜY (affected). The woman's father was XᶜY, so she must have inherited Xᶜ from him; since she has normal vision, she is a carrier XᶜX. Cross: XᶜY × XᶜX → daughters: XᶜXᶜ (affected, 50%), XᶜX (carrier, 50%); sons: XᶜY (affected, 50%), XY (normal, 50%). So 50% of sons and 50% of daughters will be affected — overall 50% of children affected.

Revision

Key formulas at a glance

Memorise these before attempting numericals — most exam questions hinge on one of them.

Monohybrid ratio

F2 phenotypic ratio=3:1\text{F}_2 \text{ phenotypic ratio} = 3:1

Dihybrid ratio

F2 phenotypic ratio=9:3:3:1\text{F}_2 \text{ phenotypic ratio} = 9:3:3:1

Test cross ratio

Test cross: Tt×tt1:1 (tall : dwarf)\text{Test cross: } \text{Tt} \times \text{tt} \rightarrow 1:1 \text{ (tall : dwarf)}

Genotypic ratio (monohybrid)

F2 genotypic ratio=1:2:1\text{F}_2 \text{ genotypic ratio} = 1:2:1

Chromosome number

2n=46 (22 pairs autosomes + XX or XY)2n = 46 \text{ (22 pairs autosomes + XX or XY)}

Down syndrome karyotype

2n=47 (trisomy 21)2n = 47 \text{ (trisomy 21)}

Recombination frequency

RF=recombinantstotal offspring×100\text{RF} = \frac{\text{recombinants}}{\text{total offspring}} \times 100

Exam tips

How this chapter is asked

Where this topic appears in CBSE, JEE Main and NEET papers.

  • Mendel chose pea because it has short life cycle, pure lines and easily distinguishable traits.
  • Monohybrid F₂ ratio is 3:1; dihybrid F₂ ratio is 9:3:3:1 — must-know for NEET.
  • Incomplete dominance gives 1:2:1 F₂ ratio for both genotype and phenotype (e.g. snapdragon).
  • Co-dominance: both alleles expressed equally (ABO blood groups: AB type has both A and B antigens).
  • Colour blindness and haemophilia are X-linked recessive — more common in males, criss-cross inheritance.
  • Males cannot transmit X-linked traits to sons (father gives Y chromosome).
  • Down syndrome is trisomy 21 (2n = 47), Turner is XO (2n = 45), Klinefelter is XXY (2n = 47).
  • Pedigree: skip generation = recessive; every generation = dominant; equal sex ratio = autosomal.

FAQ

Common questions

What is the difference between incomplete dominance and co-dominance?

In incomplete dominance, the heterozygote shows a blended intermediate phenotype (e.g. pink flowers from red × white). In co-dominance, both alleles are fully and simultaneously expressed in the heterozygote (e.g. AB blood type shows both A and B antigens). The key difference is blending vs simultaneous full expression.

Why are sex-linked disorders more common in males?

Males have only one X chromosome (XY), so a single recessive allele on the X chromosome will be expressed because there is no second X to mask it. Females (XX) need two copies of the recessive allele to be affected; one copy makes them carriers. This is why haemophilia and colour blindness are far more common in males.

How does a test cross help determine the genotype?

A test cross involves crossing the individual with an unknown genotype with a homozygous recessive individual. If the unknown is homozygous dominant, all offspring show the dominant trait. If it is heterozygous, approximately half the offspring show the recessive trait (1:1 ratio). The test cross reveals hidden recessive alleles.

What is the significance of linkage mapping?

Linkage mapping determines the relative positions of genes on a chromosome using recombination frequencies. Genes farther apart have higher recombination frequencies. One map unit (centimorgan) equals 1% recombination. This helps predict the likelihood of genes being inherited together and is useful in genetic counseling and genome studies.

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