Class 11 Maths Notes
Complete, exam-ready notes on probability: random experiments and outcomes, sample spaces and events, the axiomatic approach to probability, complementary events, the addition theorem, mutually exclusive events, and odds in favour and against — written for CBSE boards and JEE/NEET revision.
Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali
Probability measures the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain), calculated as the ratio of favourable outcomes to total outcomes in the sample space.
A process whose result is not determined in advance and can be one of several possible outcomes. Rolling a die, tossing a coin, or drawing a card from a deck are all random experiments.
The set of all possible outcomes of a random experiment. For a coin toss, S = {H, T}; for a die, S = {1, 2, 3, 4, 5, 6}. A sample space is exhaustive (covers all outcomes) and mutually exclusive (no two outcomes occur simultaneously).
Quick check
If events are both mutually exclusive and exhaustive, their probabilities sum to 1. This is the basis for the axiomatic definition of probability.
For any two events A and B, the probability that at least one occurs is: . The intersection term is subtracted because outcomes in both A and B are counted twice.
Two events are mutually exclusive if they cannot happen at the same time: , so . Rolling a 3 and rolling a 5 on a single die are mutually exclusive.
Odds in favour of event A are the ratio . If P(A) = 3/5, odds in favour are 3:2. Odds against A are — the reverse ratio.
Example: Two dice are thrown. Find the probability that the sum is 7.
Solution: Total outcomes = 6 × 6 = 36. Favourable pairs summing to 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — 6 outcomes. Probability = 6/36 = 1/6.
Example: From a pack of 52 cards, one card is drawn. Find the probability that it is either a king or a heart.
Solution: P(king) = 4/52, P(heart) = 13/52, P(king of hearts) = 1/52. By the addition theorem, P(king or heart) = 4/52 + 13/52 − 1/52 = 16/52 = 4/13.
Revision
Memorise these before attempting numericals — most exam questions hinge on one of them.
Classical probability
Probability bounds
Complementary event
Addition theorem
Mutually exclusive intersection
Mutually exclusive addition
Odds in favour
Exam tips
Where this topic appears in CBSE, JEE Main and NEET papers.
FAQ
Mutually exclusive events cannot occur together (P(A ∩ B) = 0); independent events do not affect each other's probability (P(A ∩ B) = P(A)·P(B)). They are distinct concepts.
If P(A) = p, odds in favour = p:(1−p). If odds are a:b, then P(A) = a/(a+b).
Use it when you need the probability of A or B (at least one occurring). Subtract P(A ∩ B) to avoid counting shared outcomes twice.
A sure event is the entire sample space S — it includes every possible outcome. Its probability is always 1.
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