Class 12 Physics Notes
Complete, exam-ready notes on semiconductor electronics: energy bands and doping, the p-n junction diode and its biasing, rectifiers, LED, photodiode and solar cell, transistors as amplifiers, and logic gates — written for CBSE boards, JEE and NEET revision.
Written byDeep Narayan· Science & Mathematics EducatorReviewed byPushpanjali
Semiconductor electronics harnesses the controlled conductivity of doped silicon and germanium to make diodes, transistors, rectifiers and logic gates — the building blocks of all modern digital devices.
In solids, atomic levels broaden into bands: the valence band (filled) and the conduction band (empty or partial). A material is a conductor, semiconductor or insulator depending on the band gap — for silicon about 1.1 eV and germanium about 0.7 eV.
Doping, not new charge
Doped crystals stay electrically neutral overall. Doping changes the ratio of electrons to holes — it does not add net charge, and the product nₑ×nₕ stays fixed for a given temperature.
At a p-n junction, electrons and holes diffuse across and recombine, leaving a thin layer (≈1 μm) of immobile ions with no free carriers. Its built-in barrier potential is about 0.7 V for silicon and 0.3 V for germanium.
Converting AC to DC. A half-wave rectifier conducts for one half-cycle only; a full-wave rectifier (centre-tap or bridge) conducts on both halves, giving a smoother DC output.
Which bias?
LED works forward-biased, photodiode reverse-biased, solar cell works as a generator. This 'who is biased which way' distinction is a recurring board and JEE favourite.
A three-layer device in n-p-n or p-n-p form with three terminals: emitter (E), base (B) and collector (C). A small base current controls a much larger collector current , giving current gain .
Digital circuits that work with two voltage levels, 0 (low) and 1 (high). The basic gates are NOT, AND, OR, NAND, NOR and XOR, each with a truth table defining its output.
Universal-gate question
A standard exam question: 'Which single gate can build everything else?' The answer is NAND or NOR. Remember NAND = AND + NOT.
Example: In a common-emitter amplifier, , and . Find the voltage gain.
Solution: . The magnitude is 200 and the negative sign shows the output is an inverted (180° phase-shifted) copy of the input.
Revision
Memorise these before attempting numericals — most exam questions hinge on one of them.
Diode current
Transistor currents
Current gain
CE voltage gain
Output waveform (full-wave)
Exam tips
Where this topic appears in CBSE, JEE Main and NEET papers.
FAQ
It is the thin ionised layer at a p-n junction with no free charge carriers. It contains immobile positive and negative ions and creates the built-in barrier potential.
Forward bias shrinks the depletion region and barrier so carriers can cross; reverse bias widens it, blocking current. This asymmetry is the basis of rectification.
An ordinary diode is used forward-biased; a Zener is specially doped to work in the reverse-breakdown region, where the voltage stays almost constant — used for voltage regulation.
Because any digital function — NOT, AND, OR, XOR — can be realised using only NAND gates (or only NOR gates), so whole circuits can be built from them alone.
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