Class 12 Physics Notes
~9 min readWave Optics Class 12 Notes
Complete, exam-ready notes on wave optics: Huygens' principle, reflection and refraction of plane waves, interference and Young's double-slit experiment, diffraction and polarisation — written for CBSE boards, JEE and NEET revision.
What is wave optics in one line?
Wave optics treats light as a wave, explaining interference, diffraction and polarisation — phenomena that the ray (geometrical) model cannot account for.
Huygens' Principle
Huygens' principle
Every point on a wavefront acts as a source of secondary spherical wavelets. The new wavefront at a later time is the envelope of all these secondary (Huygens') wavelets travelling at the wave speed.
- A wavefront is a surface of constant phase.
- Spherical wavefronts come from a point source; plane wavefronts from a distant source.
- Using Huygens' construction, the laws of reflection and refraction (Snell's law) are derived geometrically.
Reflection and refraction
Interference of Light
Coherent sources
Sources with a constant phase difference emit coherent waves that produce a stable interference pattern of bright and dark fringes. Two independent light sources are incoherent — they need a single source split in two.
- Constructive interference (bright fringe): path difference = an integral multiple of wavelength.
- Destructive interference (dark fringe): path difference = a half-integral multiple of wavelength.
- The principle of superposition governs the resultant amplitude or intensity.
Young's Double-Slit Experiment
Fringe width
The spacing between successive bright (or dark) fringes. Narrower slits and longer wavelengths widen the fringes; moving the screen farther increases .
- Path difference to a point at angle θ:
- .
- Bright fringes when
- , dark when
- .
- Intensity at a point:
- .
Monochrome needed
Diffraction
Diffraction
The bending and spreading of light as it passes an edge or through a narrow slit. Single-slit diffraction produces a central maximum flanked by weaker secondary maxima.
Interference vs diffraction
Polarisation
Polarisation
Confining the vibrations of a light wave to a single plane. This is possible for transverse (light) waves, not longitudinal waves — polarisation proves light is transverse.
- Brewster's law: at the polarising angle
- , the reflected and refracted rays are at right angles.
- A polaroid transmits vibrations along its transmission axis; crossed polaroids block light completely.
- Intensity after a polaroid at angle θ (Malus's law):
- .
Solved Examples
Example: In Young's experiment, slits are 0.2 mm apart and the screen is 1 m away with green light of wavelength 500 nm. Find the fringe width.
Solution: .
NCERT Exercise Questions
From the textbook
Exercises (NCERT Q10.1–Q10.6)
- 10.1) Monochromatic light of wavelength 589 nm is incident from air on a water surface. What are the wavelength, frequency and speed of (a) reflected, and (b) refracted light? Refractive index of water is 1.33.
- 10.2) What is the shape of the wavefront in each of the following cases: (a) Light diverging from a point source. (b) Light emerging out of a convex lens when a point source is placed at its focus. (c) The portion of the wavefront of light from a distant star intercepted by the Earth.
- 10.3) (a) The refractive index of glass is 1.5. What is the speed of light in glass? (Speed of light in vacuum is 3.0 × 10⁸ m s⁻¹) (b) Is the speed of light in glass independent of the colour of light? If not, which of the two colours red and violet travels slower in a glass prism?
- 10.4) In a Young's double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.
- 10.5) In Young's double-slit experiment using monochromatic light of wavelength λ, the intensity of light at a point on the screen where path difference is λ, is K units. What is the intensity of light at a point where path difference is λ/3?
- 10.6) A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young's double-slit experiment. (a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm. (b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide?
Answers at a glance
- 1Q10.1 → (a) Reflected: λ = 589 nm, ν = 5.09 × 10¹⁴ Hz, v = 3.0 × 10⁸ m s⁻¹. (b) Refracted: λ = 443 nm, ν = 5.09 × 10¹⁴ Hz, v = 2.26 × 10⁸ m s⁻¹.
- 2Q10.2 → (a) Spherical. (b) Plane. (c) Plane (spherical wavefront of very large radius).
- 3Q10.3 → (a) 2.0 × 10⁸ m s⁻¹. (b) No, the speed is not colour-independent; violet travels slower.
- 4Q10.4 → λ = 600 nm.
- 5Q10.5 → Intensity = K/4.
- 6Q10.6 → (a) x₃ = 1950(D/d) nm. (b) Coincidence first occurs at x = 2600(D/d) nm, where D/d is the ratio of screen distance to slit separation (values not stated in the problem).
CBSE Pattern Questions
How CBSE asks this chapter
MCQ Questions
1 Mark Questions
- 1State the condition for constructive interference in terms of path difference.
- 2Define coherence of light sources.
- 3What is the difference between interference and diffraction?
- 4State Brewster's law.
2 Mark Questions
- 1In Young's double slit experiment, λ = 600 nm, d = 1 mm and D = 1 m. Find the fringe width. (Ans: β = λD/d = 0.6 mm)
- 2Light of wavelength 500 nm in air enters glass of refractive index 1.5. Find its wavelength and speed in glass. (Ans: λ = 333 nm, v = 2 × 10⁸ m/s)
- 3Find the Brewster angle for light passing from air into glass of refractive index 1.5. (Ans: iB = tan⁻¹(1.5) ≈ 56.3°)
3 Mark Questions
- 1Derive the expression for the fringe width in Young's double slit experiment. (Ans: β = λD/d)
- 2Explain Huygens' principle and use it to establish the laws of reflection of light.
- 3Explain how polarisation of light by reflection occurs and state Brewster's law with its experimental verification.
5 Mark Questions
- 1Describe Young's double slit experiment with a ray diagram. Derive the positions of bright and dark fringes and the fringe width, and explain how the intensity distribution confirms the wave nature of light.
- 2Distinguish between interference and diffraction of light. Explain diffraction at a single slit, derive the condition for minima, and discuss why the wave nature of light is shown by diffraction but not by the particle picture.
PDF: Assignments & Tests
Printable study material
Free PDF Downloads & Assignments
Practice path: complete Assignment 1 first (topic-by-topic), then Assignment 2 (mixed difficulty with full solutions), then attempt the timed tests.
Covers all five topics: Huygens' principle; interference of light; Young's double-slit experiment; diffraction; and polarisation. Arranged topic by topic.
Higher-difficulty set with multi-topic integration problems (Huygens and Snell, interference conditions, YDSE fringe width, single-slit diffraction, polarisation) and full worked answers. Includes an answer key.
Full board-pattern test: Section A (MCQ/VSA 1M × 10), Section B (2M × 4), Section C (3M × 4), Section D (5M × 2) = 40 marks. Time: 90 minutes. Includes answer key.
Second full paper with different questions, same 40-mark / 90-minute blueprint. Includes answer key.
Quick Revision
Key formulas at a glance
Memorise these equations — direct application numericals and derivations in CBSE & JEE frequently hinge on these.
Fringe width
Bright fringe
Single-slit minima
Malus's law
Brewster's law
Refractive index
Exam Strategy
How this chapter is asked
High-yield question patterns observed across CBSE boards, JEE Main & Advanced, and NEET.
- Fringe width β = λD/d; use consistent units (metres).
- Coherent monochromatic light gives a stable fringe pattern.
- Single-slit central maximum width = 2λD/a.
- Polarisation proves light is a transverse wave.
- Brewster angle: tan i_p = n, with reflected and refracted rays perpendicular.
FAQ
Frequently asked questions
What is the difference between interference and diffraction?
Interference results from a few coherent sources and gives equally spaced fringes; diffraction results from many sources on a single slit and gives a broad central maximum with decaying secondary maxima.
Why does white light give coloured fringes?
Each wavelength interferes at slightly different path differences, so the bright fringes for different colours land at slightly different positions, producing coloured bands around a white centre.
What does polarisation tell us about light?
Only transverse waves can be polarised, so the ability to polarise light confirms it is a transverse wave and not longitudinal.
How do I increase the fringe width?
Increase the wavelength or the screen distance, or decrease the slit separation — fringe width β = λD/d.
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